The period of the pendulum is given by the following equation
T = 2<span>π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2</span>π)<span>^</span><span>2 = L/g
g = L/(</span>T /2π)^2...........> g = 22.657 m/s^2
Answer:
option B is correct
Explanation:
according to law of conservation of momentum the total momentum in a closed system remains constant before and after collision
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