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Alchen [17]
3 years ago
10

A resistor with a resistance of 2 MΩ is connected in series with a 5 µF capacitor and a battery with emf 10 V. The capacitor has

originally a charge of 5 µC and then discharged. At what time will the charge be equal to 1µC?
A. 16 sec
B. 1.6 sec
C. 3.2 sec
D. 8 sec
Physics
1 answer:
ehidna [41]3 years ago
7 0
C because it very simple
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A mercury thermometer is constructed as
Tamiku [17]

Answer:

The change in height of the mercury is approximately  2.981 cm

Explanation:

Recall that the formula for thermal expansion in volume is:

\frac{\Delta V}{V_0} =\alpha_V\, \Delta\, T\\\Delta V = V_0\,\, \alpha_V\,\,\Delta C

from which we solved for the change in volume \Delta V due to a given change in temperature \Delta T

We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

V_0=\frac{4}{3} \pi \, R^3\\V_0=\frac{4}{3} \pi \, (0.12\,cm)^3\\V_0=0.007238\,cm^3

Therefore, the change in volume with a change in temperature of 36°C becomes:

\Delta V = V_0\,\, \alpha_V\,\,\Delta C\\\Delta V = 0.007238229\, cm^3\,(0.000182)\,(36)\\\Delta V=0.0000474248\, cm^3

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):

V_{cyl}=\pi r^2\,h\\h =\frac{V_{cyl}}{\pi r^2} \\h=\frac{0.0000474248\, cm^3}{\pi \, (0.00225\,cm)^2} \\h=2.98188 \,cm

8 0
3 years ago
Elaborate on the suitability of "cola" type drinks to polish chrome surfaces.
nexus9112 [7]
The answer is t<span>he phosphoric acid in cola easily removes dirt and grime.   The </span>"cola" type drinks is suitable to polish chrome surfaces. Cola contains a very diluted solution of phosphoric acid, which can  remove rust, dirt, and grime from chrome surface. 
3 0
4 years ago
What is the magnitude of the vector described below
Romashka [77]

Answer:

D. Miles per hour

Explanation:

Have a Good Day

5 0
2 years ago
Photons with wavelength 1 pm are incident on electrons. What is the frequency of the Compton-scattered photons at an angle of 60
natali 33 [55]

Answer:

f = 1.354*10^{20} Hz

Explanation:

By conservation of linear momentum, wavelength shift due to collision of photon to electron is given by following formula

\lambda ^{'}-\lambda =\frac{h}{m_{o}c}(1-cos\theta )

where h is plank constant = 6.626*10^{-34}

c = speed of light = 3*10^{8} m/s

scattered angle  =  60 degree

m = rest mass of electron  = 9*10^{-31}

\lambda ^{'}=10^{-12} +\frac{6.626*10^{-34}}{9*10^{-31}*3*10^{8}}(1-cos60^{o} )

\lambda ^{'}= 2.215 pm

we know that 1 pm = 10^{-12}m

f = \frac{c}{\lambda ^{'}}

f = \frac{3*10^{8}}{2.215 *10^{-12}} = 1.354*10^{20} Hz

f = 1.354*10^{20} Hz

4 0
3 years ago
A volume of air increases 0.227 m^3 at a net pressure of 2.07 x 10^7 Pa. How much work is done on the air?
aliya0001 [1]

Answer:

The work done on the air is 4.699 x 10⁶ Joules

Explanation:

Given;

increase in air volume, ΔV = 0.227 m³

net pressure of the air, P = 2.07 x 10⁷ Pa

The work done on the air is given by;

W = PΔV

Where;

W is the work done on the air

P is the net pressure

ΔV  is the increase in air volume

Substitute the given values and solve for work done;

W = (2.07 x 10⁷ Pa) (0.227 m³)

W = 4.699 x 10⁶ Joules

Therefore, the work done on the air is 4.699 x 10⁶ Joules

7 0
3 years ago
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