If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
Answer:
See below for answers and explanations
Step-by-step explanation:
<u>Part A</u>
The average rate of change of a function over the interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
is equal to 
, hence:
Therefore, the average rate of change of 
over the interval ![[5,9]](https://tex.z-dn.net/?f=%5B5%2C9%5D)
is 
.
<u>Part B</u>
Do the same thing as in Part A:
Therefore, the average rate of change of 
over the interval ![[0.25,1]](https://tex.z-dn.net/?f=%5B0.25%2C1%5D)
is 
.
<u>Part C</u>
To interpret our answer from Part B in terms of the real world it represents, we say that between 0.25 seconds and 1 second, the ball falls at a rate of 4 feet per second (since our average rate of change is negative).
The general equation of the circle is expressed as (x-h)2 + (y-k)2 = r2 where (h,k) is the center of the circle. we are are given the center of the circle at (0,0) so the expression is simplified to <span>(x)2 + (y)2 = r2. given the other point, r2 is equal to 41. hence the final equation is x2 + y2 = 41</span>
It seems that the four graphs are the same and they do not have a negative change rate in the interval 0 to 2 in the x-axis.
A negative change rate means that when x increases the value of the function (y) decreases; this is, the function is decreasing in the interval being estudied, which is the same that going downward.
So, you must look for in your graphs where the equation is going downward.
For example, in the graph attached, that happens in any interval from negative infitity to 1.5.
The vertex will help you to identify it.
Given that the graph goes downward from negative infinity to the vertex, any interval that includes that range will have negative change.
You must look for a parabola that opens upward and whose vertex is in x = 2.
Read more on Brainly.com - brainly.com/question/3774202#readmore
Answer:
(2,0)
Step-by-step explanation:
Take the average of the two x-coordinates: (10-6)/2 = 2
Take the average of the two y-coordinates: (4+(-4))/2 = 0
Midpoint: (2,0)
