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2 years ago

Choose the slope-intercept form of y + 3 = 4(x - 5).

Mathematics

2 answers:

Scrat [10]2 years ago

5 0

Answer: y=4x-23

Step-by-step explanation:

First multiply the 4 on the right side to make it y+3=4x-20. Then subtract 3 on both sides to get y=4x-23

DerKrebs [107]2 years ago

5 0

Answer:

Below.

Step-by-step explanation:

Distributive property

y + 3 = 4(x - 5)

y + 3 = 4x - 20

Combine like terms..

y + 3 = 4x - 20

-3 . - 3

y = 4x - 23

Hope this helps.

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3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

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2 years ago

Helppppppppppppppppppp helppppppppppppp

Annette [7]

HOPE ITS HELPFUL ^_^

<h2>•RHONA</h2>

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2 years ago

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Answer:

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