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tekilochka [14]
4 years ago
7

Determine which system below will produce infinitely many solutions.

Mathematics
2 answers:
vesna_86 [32]4 years ago
8 0
First task:
To determine this we need to make difference between system that doesn't have solution and system that has infinite number of solution. If when solving equations we get   0 = 0 that means system has infinite number of equations.
If we get 0 = some number that means that system doesn't have solution.

Multiplying first equation of second system by 2 and adding it to second equation we get 0=0 which means that this system has infinite number of solutions.

Answer is second system

Second task:
For this we need to set a system of equations and solve it. System looks like this:
x + y = 224
x*12 + y*8=2520
-------------------------
x represents older than 18 and "y" 18 and younger than that.
first equation we multiply with -12 and sum it with second.
-4y = -168
y=168/4 = 42

Answer is 42.
frosja888 [35]4 years ago
6 0
-2x + 4y = 18
<span>4x - 8y = -36

This system has infinite solutions as one equation is a factor of the other
 
for the second we can check that 
a number of visitors older than 18
b number of visitors  younger than 18

a(12) +b(8) = 2520
a + b = 224

solving the equation system we have 
that 182 visitors were 18 or younger

</span>
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masya89 [10]

Answer:

1) Please find the attached drawing of the archway created with MS Excel

2) The y-intercept is (0, 24)

The x-intercepts are (-3, 0), and (8, 0)

3) The width of the archway at its base is 11

The height of the archway at its highest point = 30.25

Step-by-step explanation:

The given function representing the archway is y = -x² + 5·x + 24

1) Please find attached the required drawing of the archway created with MS Excel

2) The y-intercept is given by the point where x = 0

Therefore, we have, the y-value at the y-intercept = -0² + 5×0 + 24 = 24

The y-intercept = (0, 24)

The x-intercept is given by the point where y = 0

Therefore, the x-values at the x-intercept are found using the following equation;

0 = -x² + 5·x + 24

x² - 5·x - 24 = 0

By inspection, we have;

x² - 8·x + 3·x - 24 = 0

x·(x - 8) + 3·(x - 8) = 0

∴ (x + 3) × (x - 8) = 0

Either (x + 3) = 0, and x = -3, or (x - 8) = 0, and x = 8

Therefore, the x-intercepts are (-3, 0), and (8, 0)

3) The width of the archway at its base = The distance between the x-values at the two x-intercepts

∴ The width of the archway at its base = 8 - (-3) = 11

The highest point of the arch is given by the vertex of the parabola, y = a·x² + b·x + c, which has the x-value of the vertex = -b/(2·a)

∴ The x-value of the vertex of the given parabola, y = -x² + 5·x + 24, is x = -5/(2×(-1)) = 2.5

Therefore;

The y-value of the vertex, is y = -(2.5)² + 5×2.5 + 24 = 30.25 = The height of the archway at its highest point

∴ The height of the archway at its highest point = 30.25.

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There are 7 boys in the class and 17 girls
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