Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
The answer is 20
Your welcome
Answer:
sure
Step-by-step explanation:
U/9 = 8/12 u = 6
Step 1: Cancel the common factor (4)
u = 2
—- —-
9 3
Step 2: multiply both sides by 9
9u 2 * 9
—- = ——-
9 3
Step 3: simplify
2 *9 = 18
18 ÷ 3 = 6
u = 6
Answer:
First option
Step-by-step explanation:
You can plug in values and verify.
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