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Igoryamba
3 years ago
9

A class consists of 55% boys and 45% girls. It is observed that 25% of the class are boys and scored an Aon the test, and 35% of

the class are
girls and scored an A on the test.
If a student is chosen at random and is found to be a girl, the probability that the student scored an Als
Mathematics
1 answer:
Korvikt [17]3 years ago
3 0
Total percentages of student who scored As
= 25+35= 60%
Probability of a girl who got A = 35/60
If you simplify the ans will be 7/12
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Grace and her brother Sid want to raise money to go to band camp. Their parents have agreed to help them earn up to $400 by payi
LenKa [72]

Answer:

25m + 10b = 400

Step-by-step explanation:

Total amount that can be earned = $ 400

Amount earned on mowing a lawn = $ 25

Amount earned per hour on babysitting = $10

Amount earned for mowing one lawn is $ 25, so amount earned for mowing m lawns will be $ 25m

Amount earned for one hour of babysitting is $ 10, so amount earned for babysitting for b hours will be $ 10b

Total amount earned = Amount earned from mowing m lawns + Amount earned from babysitting for b hours

Using the values from above, we can set up the equation as:

400 = 25m + 10b

or

25m + 10b = 400

This equation represents the number of lawns they can mow, m, and hours they can babysit, b, to earn $400.

3 0
3 years ago
The function d =
Nuetrik [128]

Answer:

continuous

Step-by-step explanation:

Since the function d=45t can have numbers in between and time is constantly happening, he does not hop, or skip at 1 second, then 5 seconds...he is continuously traveling, so time = 1 sec, 1.1 sec., 1.1000001, 1.000002, etc. time does not stop therefore if you graphed this, you would connect the dots, therefore, it is continuous

3 0
3 years ago
A small combination lock on a suitcase has 4 ​wheels, each labeled with the 10 digits 0 to 9. how many 4 digit combinations are
tamaranim1 [39]
This is the easiest way to solve this problem:

Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __

For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot 
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7 
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations


For the next two do the same process as the one above.

If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations

If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.

<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>

10*9*9*9 = 7290 combinations






8 0
3 years ago
Find the product.
4vir4ik [10]
Answer :

6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}

Step-by-step explanation :

To find the product of

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)

we now apply the law of indices

{a}^{m} \times {a}^{n} = {a}^{m+n}

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}
3 0
3 years ago
What is the answer to <br> 20/$23.80
kari74 [83]

Answer: .84

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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