Answer:
HAAAAA U IN SOME DEEP S***
Explanation:
Answer:
di ko gets haha yawa ka jj
B or two relative <span>abundance of each isotope</span>
0.0340 g O2
<em>Step 1.</em> Write the balanced chemical equation
4Fe(OH)^(+) + 4OH^(-) + O2 + 2H2O → 4Fe(OH)3
<em>Step 2</em>. Calculate the moles of Fe^(2+)
Moles of Fe^(2+) = 50.0 mL Fe^(2+) × [0.0850 mmol Fe^(2+)/1 mL Fe^(2+)]
= 4.250 mmol Fe^(2+)
<em>Step 3</em>. Calculate the moles of O2
Moles of O2 = 4.250 mmol Fe^(2+) × [1 mmol O2/4 mmol Fe^(2+)]
= 1.062 mmol O2
<em>Step 4</em>. Calculate the mass of O2
Mass of O2 = 1.062 mmol O2 × (32.00 mg O2/1 mmol O2) = 34.0 mg O2
= 0.0340 g O2
Answer: the correct answer for soapy water is basic pH=11 and for sea water it is neutral pH=7
Explanation:
On edgunity those are the correct answers
