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<h3>Answer:</h3>
1000 g CCl₄
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Step 1: Define</u>
3.93 × 10²⁴ molecules CCl₄
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of CCl₄ - 12.01 + 4(35.45) = 153.81 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1003.77 g CCl₄ ≈ 1000 g CCl₄
