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Dimas [21]
3 years ago
14

Kp for the following reaction is 0.16 at 25 degree C. 2 NOBr(g) 2 NO(g) Br_2(g) The enthalpy change for the reaction at standard

conditions is
Chemistry
1 answer:
finlep [7]3 years ago
5 0

Answer:

Explanation:

Given that:

2 NOBr_{(g)} \iff 2 NO_{(g)} + Br_{2(g)}

From above:

K_p = 0.16 = \dfrac{(P_{NO})^2 (P_{Br})}{(P_{NOBr})^2}

To predict the effect of the addition of Br₂(g);

The addition of Br₂(g) will favor the equilibrium to shift to the left i.e. formation of NOBr

The removal of some NOBr will cause the equilibrium position to shift to the left side. This is because concentration on the left side is decreased and the concentration on the right side will be increased. Thus, the equilibrium will shift towards where the concentration is reduced which is the left side.

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Novosadov [1.4K]

Answer:

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6 0
2 years ago
Two gas-filled tanks have the same volume, temperature, and pressure. They are identical in every way except that one is filled
Tems11 [23]

Answer:

The tank with O₂ weighs more.

Explanation:

We can find the mass of gas using the ideal gas equation.

P.V=n.R.T=\frac{m}{M} .R.T\\m=\frac{P.V.M}{R.T}

Considering the pressure (P), volume (V), temperature (T) and ideal gas constant (R) are the same, we can establish that:

m ∝ M

The mass is directly proportional to the molar mass. The molar mass of O₂ (32 g/mol) is higher than the molar mass of N₂ (28 g/mol). Therefore, the tank with O₂ weighs more.

8 0
3 years ago
How does the shape of the Earth affect the climate of different regions?<br><br>will give brainliest
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Because the Earth<span> is a sphere, the surface gets much more intense sunlight, hence heat, at the equator than at the poles.</span>
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7 0
3 years ago
The equilibrium constant k for the synthesis of ammonia is 6.8x105 at 298 k. what will k be for the reaction at 375 k?
spayn [35]
Answer is: K <span>be for the reaction at 375 K is 326.
</span>Chemical reaction: N₂(g) + 3H₂(g) ⇌ 2NH₃(g); ΔH = -92,22 kJ/mol.
T₁<span><span> = 298 K
</span>T</span>₂<span><span> = 375 K
</span><span>Δ<span>H = -92,22 kJ/mol = -92220 J/mol.
R = 8,314 J/K</span></span></span>·mol.<span>
K</span>₁ = 6,8·10⁵.<span>
K</span>₂ = ?The van’t Hoff equation: ln(K₂/K₁) = -ΔH/R(1/T₂ - 1/T₁).
ln(K₂/6,8·10⁵) = 92220 J/mol / 8,314 J/K·mol (1/375K - 1/298K).
ln(K₂/6,8·10⁵) = 11092,13 · (0,00266 - 0,00335).
ln(K₂/6,8·10⁵) = -7,64.
K₂/680000= 0,00048
K₂ = 326,4.
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3 years ago
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