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expeople1 [14]
2 years ago
7

If four bells toll at intervals of 8,9,12 and 15 minutes respectively. If they toll at 3 pm when will they toll together

Mathematics
1 answer:
miv72 [106K]2 years ago
7 0
Ur basically looking for the common multiple of the numbers 8,9,12,and 15.
LCM of these numbers is 360. 

so 360 minutes = (360/60) = 6 hrs

and 6 hrs from 3 p.m. would be : 9 p.m. <== ur answer
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Work Shown:

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maw [93]
F(x,n,p)=C(n,x)p^x*(1-p)^(n-x)
n=9, p=0.8  =>
f(x,9,0.8)=C(9,x)0.8^x*(0.2)^(9-x)

The function f(x,9,0.8) is then calculated using the above formula
x f(x)
0 0.0000001 0.0000182 0.0002953 0.0027534 0.0165155 0.0660606 0.1761617 0.3019908 0.3019909 0.134218

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4 0
2 years ago
How to solve this one​
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4 0
2 years ago
A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud
iris [78.8K]

Answer:

-0.048

Do not reject  H_0:P_1-P_2=0

Step-by-step explanation:

From the question we are told that

Sample size n_1=350

Sample size n_2=250

Sample proportion 1  \hat P= \frac{25}{350} =>0.07

Sample proportion 2 \hat P= \frac{19}{250} =>0.076

95% confidence interval

Generally for 95% confidence level

Level of significance

 \alpha = 1-0.95=>0.05

 \alpha /2=\frac{0.05}{2} =>0.025

Therefore

Z_a_/_2=1.96

Generally the equation for confidence interval between P_1 - P_2  is mathematically given as

(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2}  }

(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250}  }

(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4  }

(-0.006)\pm 0.042

(-0.006)- 0.042=>-0.048

(-0.006)+ 0.042=>0.036

Therefore

Confidence interval is

-0.048

Conclusion

Given the confidence interval has zero

Therefore do not reject  H_0:P_1-P_2=0

6 0
2 years ago
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