Because bryce started off with $450 , then his a1 should be $450. Then the amount of money that he will have after one month is
an = 13(an-1)
In this case, an is the amount of money he has and an-1 is the amount of money he has in his account from the month prior
Answer:
3
Step-by-step explanation:
The assumed frequency of defects is 2/16.
When we apply this rate to 24, (2/16)*24, we get 3.
Therefore, we can assume around 3 defective boxes tomorrow.
5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)
I hope it helps
Answer:
$60
Step-by-step explanation:
Jason saved gas money (x). Maria saved $20 more than double what Jason has (20 + 2x). Combined, they saved $200. Solve for x for Jason's amount.
(x) + (20 + 2x) = 200
x + 20 + 2x = 200
3x + 20 = 200
3x + 20 = 200
3x + 20 - 20 = 200 - 20
3x = 180
3x/3 = 180/3
x = 60
Jason saved $60 for this trip.
Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 99% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.575.
The estimate and the sample size are given by:
.
Then the bounds of the interval are:
The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
More can be learned about the z-distribution at brainly.com/question/25890103
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