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aniked [119]
2 years ago
13

There are currently 3 people signed up for the debate club. The school will not recognize the club officially until it has more

than 5 members.
Which of the following graphs includes the possible values for the number of people who still need to sign up to make the club "official?"

A. Number line with closed circle on 2 and shading to the left.
B. Number line with closed circle on 2 and shading to the right.
C. Number line with open circle on 2 and shading to the left.
D. Number line with open circle on 2 and shading to the right.

Mathematics
1 answer:
vodomira [7]2 years ago
5 0
D because it does not have shaded, it’s not shaded so it does not include 2, and 3 and up people need to join the club still for it to be official
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Charlie invested $12,000 into an
IrinaK [193]

Answer:

$1800

Step-by-step explanation:

12000(1+0.05x 3)

= 13800

13800 - 12000

$1800

3 0
3 years ago
Circle O is shown below. the diagram is not drawn to scale. 73°
zepelin [54]
Answer:
53.5

Explanation:
Since triangle AOB is an isosceles triangle (AO = OB), the base angles of the triangle are 53.5. (180-73 = 107, 107/2 = 53.5)
8 0
2 years ago
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Craig Browning bakes cookies for the elementary school cookie sale. His chocolate chip cookies sell for $1.00 a dozen, and his o
Volgvan

Answer and Step-by-step explanation:

Let

Number of chocolate chip cookies = x

Number of oatmeal brownie cookies = y

Bake chocolate chip cookies up to 20 dozen = x≤ 20

Bake oatmeal brownies up to 40 dozen= y≤40

Total cookies = x + y ≤ 50

Number of oatmeal brownie will be no more than three times the number of chocolate chip= y≤3x

From the inequality:

                        X + y=50                          

                         y = 3x

By putting the value of y, we get

    x + 3x = 50

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By putting the value of x=12.5 in equation y = 3x, we get

Y = 3(12.5)

    = 37.5

Craig should make 12.5 dozen chocolate chip and 37.5 dozen oatmeal brownies in order to make more money.

8 0
3 years ago
In each part, decide if the statement is true. If it is true, prove it. If it is not true, give an explicit counterexample and d
svet-max [94.6K]

Answer: Hello!

ok, remember that "if and only if" implies that you need to prove the statement in both ways, this is represented with the ⇔ usually.

a) For any sets A, B and C, A ∩ B ⊆ C if and only if either A ⊆ C or B ⊆ C.

In this type of problems, i  find very useful start looking for some counterexample.

In this case, suppose that A = {1,2,3,4,5} , B = {3,4,5,6,7} and C = {3,4,5,6}

then is easy to see that A ⊄ C and B ⊄C.

And A∩B = {3,4,5}

then A∩B ⊂ C

then the statement is false (because one of the ways is false, remember that this is an "if and only if" statement)

b) For any sets A, B and C, A ⊆ B ∩ C if and only if both A ⊆ B and A ⊆ C.

the first way is true; because if A ⊆ B ∩ C. then all the elements of A are in the intersection of B and C (which are common elements for B and C) and then all the elements of A are in the set B and in the set C, and this means that A ⊆ B and A ⊆ C.

But let's see the other way now, suppose that A ⊆ B and A ⊆ C, now we want to know if A ⊆ B ∩ C.

if A ⊆ B and A ⊆ C, means that all the elements of A are in B, and all the elements of A are in C, then all the elements of A are common elements between B and C, this means that B ∩ C is at least equal to A (at least, because we know that all the elements of A are common elements between B and C, but there could be more common elements that don belong to A)

then A ⊆ B ∩ C.

4 0
3 years ago
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Anna35 [415]

Answer:

c

Step-by-step explanation:

The Africans gained a majority in the Parliament

8 0
2 years ago
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