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MariettaO [177]
4 years ago
15

How do you factor the trinomial 6^2+66x+108?

Mathematics
1 answer:
svet-max [94.6K]4 years ago
5 0
First divide through by 6, we get 

6(x^2 + 11x + 18)

= 6(x + 2)(x + 9)   Answer



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A school football team is selling raffle tickets As a fundraiser it cost them $155 to print the tickets and they would like to m
sp2606 [1]

Answer:

They need $2655 to raise to cover the costs of the printing and meet their goal.

Step-by-step explanation:

Consider the provided information.

As a fundraiser it cost them $155 to print the tickets and they would like to make at least a $2500 profit

Let x (in dollar) represents the fund raised.

The money spent on printing ticket is $155.

The profit they would like to make at least is $2500.

Therefore, the required inequality is:

x-155\geq 2500

Simplify the inequality.

x\geq 2500+155\\x\geq 2655

Therefore, they need $2655 to raise to cover the costs of the printing and meet their goal.

8 0
3 years ago
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and section B had 20 students
faltersainse [42]
B, because when you add 90+80 you get 170 and 170/2 = 85
8 0
3 years ago
Read 2 more answers
(-4x^5)^2(-2x^4)^5<br> Please help????!
ycow [4]

Answer:

-512x^{30}

Step-by-step explanation:

(-4x^5)^2 = 16x^{10}\\(-2x^4)^5 = -32x^{20}\\16x^{10} * -32x^{20} = -512x^{30}

8 0
3 years ago
84/100 into a percentage
Allushta [10]
84/100 converted to percent is 84%.
4 0
3 years ago
Read 2 more answers
If tan 0=5/4, calculate the value of cos 0
emmasim [6.3K]
 
                     5
If  tan θ  =  —— , calculate the value of  cos θ:
                     4


Recall the definition of the tangent function:

                 sin θ
tan θ  =  ————
                cos θ
 
  5           sin θ
——  =  ————
  4          cos θ

Cross multiply:

5 · cos θ = 4 · sin θ

Square both sides:

(5 · cos θ)² = (4 · sin θ)²

5² · cos² θ = 4² · sin² θ

25 · cos² θ = 16 · sin² θ

But  sin² θ = 1 – cos² θ.  Substitute that for  sin² θ  into the equation above, then you get

25 · cos² θ = 16 · (1 – cos² θ)

25 · cos² θ = 16 – 16 · cos² θ

Isolate  cos² θ:

25 · cos² θ + 16 · cos² θ = 16

(25 + 16) · cos² θ = 16

41 · cos² θ = 16
 
                    16
cos² θ  =  ———
                    41

                      4²
cos² θ  =  ————
                  (√41)²

Take square root of both sides:
 
                       4
cos θ  =  ±  ———
                    √41

                       4                                    4
cos θ  =  –  ———     or     cos θ  =  ———          ✔
                     √41                               √41


The sign of  cos θ  depends on which quadrant  θ  lies. Since you first have a positive value for  tan θ, then that means  θ  lies either in the  1st  or the  3rd quadrant.

•  If  θ  is a  1st  quadrant angle, then

cos θ > 0
 
                   4
cos θ  =  ———          ✔
                 √41

•  If  θ  is a  3rd  quadrant angle, then

cos θ < 0
 
                       4
cos θ  =  –  ———          ✔
                     √41


I hope this helps. =)

3 0
3 years ago
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