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Nookie1986 [14]

3 years ago

15

A spring with a spring constant of k = 185.0 N / m is oriented vertically, with one end on the ground. What distance does the sp

ring compress when an m = 1.53 kg object is placed on its upper end?

1 answer:

uysha [10]3 years ago

8 0

Answer:

The distance spring compresses (x) = 0.0811 m

Explanation:

Spring constant (k) = 185 N / m

mass (m) = 1.53 kg

When mass is placed upon the spring the spring force is equal to weight of the mass.

⇒ Spring force (F) = weight of object

⇒ Spring force (F) = k × x

And weight of the object = mg

⇒ k x = mg -----------------(1)

Put all the values in equation (1) we get

⇒ 185 × x = 1.53 × 9.81

⇒ x = 0.0811 m

This the distance spring compresses, when mass is placed upon it.

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<em>The average acceleration of the object is 0.5 cm/s^2</em>. Answer: A)

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$\displaystyle \bar a=\frac{v_f-v_o}{t}$

Where vf is the final speed, vo is the initial speed and t is the time.

The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

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A) Correct. The average acceleration is 0.5 cm/s^2

B) Incorrect. The average acceleration is 0.5 cm/s^2

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3 years ago

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4 years ago

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Answer:

Average velocity = 30 miles per hour

Explanation:

Given that

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Lets take distance from home to school is s

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3 years ago

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Answer:

Explanation:

Given

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