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aleksklad [387]
2 years ago
10

A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the c

ar?
Physics
1 answer:
Alborosie2 years ago
5 0

Acceleration

  • a=v-u/t
  • a=20-0)6.6
  • a=20/6.6
  • a=3.03m/s²

Now

Apply Newtons second law

  • F=ma
  • F=1000(3.03)
  • F=3030N

To find frictional force we need coefficient of friction which is not given .

generally for car case the value of coefficient is 0.6-0.8 .

Putting max 0.8

  • f=$\mu$ N
  • f=0.8(3030)
  • f=2424N

Note:

Last part is assumption not accurate

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HOLA, NECESITO AYUDA!
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The electrostatic force between the two ions is 2.9\cdot 10^{-10} N

Explanation:

The electrostatic force between two charged particle is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where

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In this problem, the ion of sodium has a charge of

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Substituting, we find the electrostatic force between the two ions:

F=(8.99\cdot 10^9) \frac{(1.6\cdot 10^{-19})(-1.6\cdot 10^{-19})}{(282\cdot 10^{-12})^2}=-2.9\cdot 10^{-10} N

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