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aleksklad [387]
2 years ago
10

A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the c

ar?
Physics
1 answer:
Alborosie2 years ago
5 0

Acceleration

  • a=v-u/t
  • a=20-0)6.6
  • a=20/6.6
  • a=3.03m/s²

Now

Apply Newtons second law

  • F=ma
  • F=1000(3.03)
  • F=3030N

To find frictional force we need coefficient of friction which is not given .

generally for car case the value of coefficient is 0.6-0.8 .

Putting max 0.8

  • f=$\mu$ N
  • f=0.8(3030)
  • f=2424N

Note:

Last part is assumption not accurate

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Here's the formula for mechanical advantage.
It's very important, and you should memorize it:

      Mechanical Advantage  =  (output force) divided by (input force) .

#1).  Force that moves the object = output force = 550N
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       Use the formula:

       (output force) divided by (input force) = 550N/200N =  2.75  . 

#2).
#3).
#4).
#5).
#6).
#7).
#8).
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All of the rest of the problems on the page tell you the input force
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7 0
3 years ago
a diver on a board 7.5m above the water walks off the end with a horizontal velocity of 2.3 m/s when they hit the surface of the
m_a_m_a [10]

Answer:

2.846m

Explanation:

The diver is performing projectile motion.

To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)

x(initial) = 0

x(final) = ?

v(initial) = 2.3 m/s

we don't know t

To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)

- 9.8 in the acceleration in the y dir.

y(final) = 0

y(initial) = 7.5

v(initial in the y dir.) = 0

If we solve for t we get: t = 1.237s

Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)

x(final) = 2.3*1.237 + 0

x(final) = 2.846m

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jenyasd209 [6]
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4 years ago
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barxatty [35]

Answer:

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Explanation:

Fossil fuels were formed from the dead remains of living organisms millions of years ago. They were formed under high pressure and high temperature.

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