Question

Students are given the following information about a 2.0 kg, motorized toy boat on water. what net force is exerted on the boat from 4S to 8S?

Answer 1

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

The motorized toy boat moves at 8 m/s (u) at 4 s and at 8 m/s (v) at 8 s. We can calculate the acceleration (a) in that period using the following kinematic expression.

$a = \frac{v-u}{\Delta t} = \frac{8m/s-8m/s}{8s-4s} = 0 m/s^{2}$

The object with a mass (m) of 2.0 kg experiences an acceleration of 0 m/s². We can calculate the net force (F) in that period using Newton's second law of motion.

$F = m \times a = 2.0 kg \times 0 m/s^{2} = 0 N$

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.

Learn more: brainly.com/question/13447525