1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
exis [7]
3 years ago
7

How many moles of atoms are in 5.00 g of 13C

Chemistry
1 answer:
Illusion [34]3 years ago
7 0
  <span>Mr = 13 g / mol 
mass = 5 g 
Mol = 5/13 mol :)</span>
You might be interested in
PLEASE HELP QUICKLY!! How many moles of NH4OH are in 0.125L of a 1.4 M solution of NH4OH?
frez [133]

Answer:

0.175mol

Explanation:

Molarity of a solution can be calculated thus:

Molarity (M) = number of moles (n) / volume (V)

According to the information provided in this question, volume of NH4OH = 0.125L, molarity = 1.4M

Using; Molarity = n/V

1.4 = n/0.125

n = 0.175mol

5 0
3 years ago
How can you determine an object mechanical energy
Dafna1 [17]
Objects have mechanical energyif they are in motion and/or if they are at some position relative to a zero potential energy position (for example, a brick held at a vertical position above the ground or zero height position). A moving car possesses mechanical energydue to its motion (kineticenergy).
7 0
3 years ago
Read 2 more answers
18. The mass of a quantity of NiCl2 is 24.6 g. How many formula units are in the sample?
Charra [1.4K]

Answer is: A. 1.1 3 1023 NiCl2 formula units.

m(NiCl₂) = 24.6 g; mass of nickel(II) chloride.

M(NiCl₂) = 129.6 g/mol; molar mass of nickel(II) chloride.

n(NiCl₂) = m(NiCl₂) ÷ M(NiCl₂).

n(NiCl₂) = 24.6 g ÷ 129.6 g/mol.

n(NiCl₂) = 0.19 mol; amount of nickel(II) chloride.

Na = 6.022·10²³ 1/mol; Avogadro constant.

N(NiCl₂) = n(NiCl₂) · Na.

N(NiCl₂) = 0.19 mol · 6.022·10²³ 1/mol.

N(NiCl₂) = 1.13·10²³; number of formula units.

4 0
3 years ago
Read 2 more answers
What would the word equation be?
valentinak56 [21]
The problem=the equation
5 0
3 years ago
How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

\tt \dfrac{1}{1}\times 4.41=4.41

mass CaCO₃(MW=100 g/mol) :

\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g

6 0
3 years ago
Other questions:
  • Determine the overall charge on each complex.a) tetrachlorocuprate(i)b) pentaamminechlorocobalt(iii)c) diaquadichloroethylenedia
    9·1 answer
  • What are the properties of carbon dioxide?
    13·1 answer
  • How is the half-life of a radioactive material useful for radioactive dating?
    5·1 answer
  • When the equation: __al2(so4)3 + __zncl2 → __alcl3 + __znso4 is correctly balanced using the smallest whole number coefficients,
    7·2 answers
  • Which reaction is an example of heterogeneous catalysis?
    13·1 answer
  • A sheet of aluminum foil weighs 2.07g. If the sheet is 24cm long and 20cm wide, how thick is the sheet in micrometers? The densi
    10·1 answer
  • Based on their number of valence electrons, which group of elements will gain two electrons by bonding with other atoms?
    10·2 answers
  • Ammonia reacts with hypobromite OBr- as follows: NH3 OBr- ---&gt; N2 Br- H20 which is the limiting reactant if 5.00 ml of 0.623
    13·1 answer
  • Which of the following accurate describes the atmospheric conditions required for the formation of clouds
    15·1 answer
  • Tobias notices that a particular kind of flower comes in many slightly different shades of pink. In other places, the same flowe
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!