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777dan777 [17]
3 years ago
11

Which of the following has the largest atomic radius: F-, F, CL-, or CL?

Chemistry
2 answers:
Anna007 [38]3 years ago
6 0
As you go down the table, more electron shells are added to make the radius larger, but as you go to the right, the protons' attraction increases so the radius actually shrinks. <span>Therefore, according to the trend, Cl has a larger radius because it is lower in the table.</span>


Answer: CL has a larger Atomic Radius.
insens350 [35]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

More is the number of electrons present in an atom more will be its atomic size.

Atomic number of fluorine is 9 which means in neutral state a fluorine atom has only 9 electrons.

But when one electron is gained by a neutral fluorine atom then it changes into F^{-} ion and there will be a total of 10 electrons in it.

On the other hand, atomic number of chlorine is 17 which means in neutral state a chlorine atom has only 7 electrons.

And, when this neutral chlorine atom gains an electron then it will form Cl^{-} ion. Hence, total number of electrons present in a Cl^{-} ion is 18.

Therefore, a Cl^{-} ion has more number of electrons that is, 18 out of the given species.

Thus, we can conclude that atomic radius of Cl^{-} ion is the largest.

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Nonpolar covalent bonds are chemical bonds where two atoms share a pair of electrons with each other and the electronegativities of the two atoms are equal. An example is methane. It has four carbon-hydrogen single covalent bonds. These bonds are nonpolar because the electrons are shared equally.
8 0
3 years ago
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In a 28 g serving of cheese curls there are 247mg of sodium. How much sodium is in a 12.5 ounce bag
Marina86 [1]

Answer:

There should be about 3136.9mg of Na in a 12.5oz bag of cheese curls.when rounding if not rounded it would be 3126.04082143mg

Explanation:

12.5oz=354.4g

354.4/28=12.7

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6 0
3 years ago
List four ways that scientific information is communicated to the general public
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5 0
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Calculate the ph of a 0.20 m solution of iodic acid (hio3, ka = 0.17).
saveliy_v [14]
Iodic acid partially dissociates into H+ and IO3- 
Assuming that x is the concentration of H+ at equilibrium, and sine the equation says the same amount of IO3- will  be released as that of H+, its concentration is also X.  The formation of H+ and IO3- results from the loss of HIO3 so its concentration at equilibrium is 0.20 M - x
Ka = [H+] [IO3-] / [HIO3]; 
<span>Initially, [H+] ≈ [IO3-] = 0 and [HIO3] = 0.20; </span>
<span>At equilibrium [H+] ≈ [IO3-] = x and [HIO3] = 0.20 - x; </span>
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7 0
3 years ago
The decomposition of ammonia to nitrogen and hydrogen on a tungsten filament at 800°C is independent of the concentration of amm
finlep [7]

Answer:

Order zero

Explanation:

Let's consider the decomposition of ammonia to nitrogen and hydrogen on a tungsten filament at 800°C.

2 NH₃(g) → N₂(g) + 3 H₂(g)

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rate = k × [NH₃]ⁿ

where,

rate: reaction rate

k: rate constant

n: reaction order

When n = 0, we get:

rate = k × [NH₃]⁰ = k

As we can see, when the reaction order with respect to ammonia is zero, the reaction rate is independent of the concentration of ammonia.

7 0
3 years ago
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