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3 years ago

Which of the following has the largest atomic radius: F-, F, CL-, or CL?

2 answers:

6 0

As you go down the table, more electron shells are added to make the radius larger, but as you go to the right, the protons' attraction increases so the radius actually shrinks. <span>Therefore, according to the trend, Cl has a larger radius because it is lower in the table.</span>

Answer: CL has a larger Atomic Radius.

insens350 [35]3 years ago

3 0

Answer: Option (c) is the correct answer.

Explanation:

More is the number of electrons present in an atom more will be its atomic size.

Atomic number of fluorine is 9 which means in neutral state a fluorine atom has only 9 electrons.

But when one electron is gained by a neutral fluorine atom then it changes into $F^{-}$ ion and there will be a total of 10 electrons in it.

On the other hand, atomic number of chlorine is 17 which means in neutral state a chlorine atom has only 7 electrons.

And, when this neutral chlorine atom gains an electron then it will form $Cl^{-}$ ion. Hence, total number of electrons present in a $Cl^{-}$ ion is 18.

Therefore, a $Cl^{-}$ ion has more number of electrons that is, 18 out of the given species.

Thus, we can conclude that atomic radius of $Cl^{-}$ ion is the largest.

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State the special characteristics of maxwell-boltzman statistics

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Answer:

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2 years ago

Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so

kumpel [21]

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For $NaOH$ :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{90.0\ g}{39.997\ g/mol}$

$Moles\ of\ NaOH= 2.2502\ mol$

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

$Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M$

<u>Final concentration of NaOH = 0.75 M</u>

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3 years ago

At what point is base no longer added during a titration

maria [59]

When you doing a titration, you need to use an indicator to confirm whether the reaction is completed. When the indicator has the color change and will not change back in one minute, the reaction is finished and you don't need to add more.

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3 years ago

A tall pea plant (Tt) is crossbred with another tall pea plant (Tt). The following Punnett square shows the separated alleles fo

Luba_88 [7]

Answer:

Explanation:

when you use punnett squares, you cross the different genes with themselves. if T is in the first box on both sides, the genome will be TT. if the box lines up to tt, it will be tt. the boxes on the left use the genes' first letter and the boxes on the right use the second letter.

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3 years ago

Read 2 more answers

A cylinder with a moving piston expands from an initial volume of 0.350 L against an external pressure of 1.90 atm. The expansio

myrzilka [38]

Answer:

1.84 L

Explanation:

Using the equation for reversible work:

$W = -P*(V_{2} - V_{1})$

Where:

W is the work done (J) = -287 J.

Since the gas did work, therefore W is negative.

P is the pressure in atm = 1.90 atm.

However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K); R = 0.0821 (L*atm)/(mol*K)

Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J

$V_{1}$ is the initial volume = 0.350 L

$V_{2}$ is the final volume = ?

Thus:

(-287 J)*0.00987 (L*atm)/J = -1.9 atm*( $V_{2}$ - 0.350) L

$V_{2}$ = [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L

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3 years ago