Which of the following has the largest atomic radius: F-, F, CL-, or CL?

2 answers:

6 0

As you go down the table, more electron shells are added to make the radius larger, but as you go to the right, the protons' attraction increases so the radius actually shrinks. Therefore, according to the trend, Cl has a larger radius because it is lower in the table.

Answer: CL has a larger Atomic Radius.

insens350 [35]3 years ago

3 0

Answer: Option (c) is the correct answer.

Explanation:

More is the number of electrons present in an atom more will be its atomic size.

Atomic number of fluorine is 9 which means in neutral state a fluorine atom has only 9 electrons.

But when one electron is gained by a neutral fluorine atom then it changes into $F^{-}$ ion and there will be a total of 10 electrons in it.

On the other hand, atomic number of chlorine is 17 which means in neutral state a chlorine atom has only 7 electrons.

And, when this neutral chlorine atom gains an electron then it will form $Cl^{-}$ ion. Hence, total number of electrons present in a $Cl^{-}$ ion is 18.

Therefore, a $Cl^{-}$ ion has more number of electrons that is, 18 out of the given species.

Thus, we can conclude that atomic radius of $Cl^{-}$ ion is the largest.

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A pharmacy intern is asked to prepare 3 L of a 30% w/v solution. T he pharmacy stocks the active ingredient in 8-ounce bottles o

MariettaO [177]

Answer: The number of bottles that will be needed are 6

Explanation:

We are given:

Amount of solution, the intern is asked to prepare = 3 L = 3000 mL (Conversion factor: 1 L = 1000 mL)

Strength of solution needed = 30 % (w/v)

This means that in 100 mL of solution, the solute present is 30 grams

So, in 3000 mL of solution, the solute present will be = $\frac{30}{100}\times 3000=900g$

Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)

Conversion factor used: 1 ounce = 29.57 mL

So, $8ounce\times \frac{29.57mL}{1ounce}=236.6mL$

Amount of active ingredient present in 1 bottle = $236.6\times \frac{70}{100}=165.6g$

To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:

$\text{Number of bottles}=\frac{\text{Amount of solution to prepare}}{\text{Amount of active ingredient in 1 bottle}}$