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In-s [12.5K]
1 year ago
13

What is the de broglie wavelength of an electron (m = 9. 11 × 10-31 kg) moving at a velocity of 3. 0 × 107 m/s?

Chemistry
1 answer:
SIZIF [17.4K]1 year ago
6 0

the de Broglie wavelength of the electron moving at a velocity of 3. 0 × 107 m/s is 2.4×10∧-11nm

lambda = h/mv

The de Broglie wavelength is defined as follows: lambda = h/mv, wherein the greek letter lambda represents the wavelength, h is Planck's consistent, m is the particle's mass and v is its pace. One may also explicit mv as the particle's momentum

according to wave-particle duality, the De Broglie wavelength is a wavelength manifested in all the gadgets in quantum mechanics which determines the chance density of locating the item at a given factor of the configuration area. The de Broglie wavelength of a particle is inversely proportional to its momentum

Learn more about de Broglie wavelength  here: brainly.com/question/19052579

#SPJ4

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How many atoms of lodine(I) are in 0.156 grams of I?
CaHeK987 [17]

Answer: iodine 131 iodine 132 isotopes

Explanation:

4 0
3 years ago
Consider the reaction of NO and CO to form N2 and CO2, according to the balanced equation: 2 NO (g) + 2 CO (g) → N2 (g) + 2 CO2
Gekata [30.6K]

The image is not given in the question, it is attached below:

<u>Answer:</u> The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

<u>Explanation:</u>

In the given image:

Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms

The combination of 1 black and 2 red spheres will represent carbon dioxide (CO_2) compound

The combination of 2 blue spheres will represent nitrogen molecule (N_2)

The combination of 1 blue and 1 red sphere will represent nitrogen monoxide (NO) compound

The combination of 1 black and 1 red sphere will represent nitrogen monoxide (NO) compound

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

We are given:

Given moles of NO = 6 moles

Given moles of CO = 4 moles

For the given chemical equation:

2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)

By stoichiometry of the reaction:

If 2 moles of CO reacts with 2 moles of NO

So, 4 moles of CO will react with = \frac{2}{2}\times 4=4mol of NO

As the given amount of NO is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, CO is considered a limiting reagent because it limits the formation of the product.

Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

3 0
3 years ago
When are the products of an equilibrium reaction favored? When the reaction is endothermic. When the equilibrium constant is lar
PtichkaEL [24]
Product are favored at ...


example 2A + 3B = 5C + D    if reaction is exothermic ....delta H = NEGATIVE)


A decrease  in temperature favors the forward reaction (more product formed)
as heat is considered as a product

For the exam I have given: A decrease in pressure (volume increases as pressure decreases) .... there are more number of moles on the product side (6 in all) .....so according to LCP decreasing pressure will revert back to increase pressure and to do that equilibrium position shifts to the right (product)

decreasing concentration of product will cause a disturbance in equilibrium position....and reaction will restore its equilibrium by shifting to the  right


(I believe its like this)
3 0
3 years ago
Read 2 more answers
Chemistry question please help!!
LiRa [457]
Answer: It’s the first one
8 0
2 years ago
Will mark Brainlest ( molecular weight of ammonium sulphate)<br>step by step​
Bond [772]

Answer:

132 amu

Explanation:

ammonium sulphate is (NH_4)_{2} SO_4

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

3 0
3 years ago
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