3 years ago

What is the mass of a 10.5 cm3 cube of fresh water (density 1.00 g/cm3)?

Physics

1 answer:

Marat540 [252]3 years ago

8 0

Density=Mass/Volume
Mass= Density*volume
Mass=1*10.5
Mass=10.5 grams

You might be interested in

Which process do plants use to turn sunlight into food energy? photosynthesis cellular respiration transpiration evaporation

Aloiza [94]

The answer is A. Photosynthesis
have a good day!

5 0

3 years ago

Read 2 more answers

Mrs. Rohaley gives you a piece of iron and asks you to determine the physical and chemical properties of the metal. She wants yo

Fofino [41]

Answer:The answer is B

Explanation:

5 0

4 years ago

PLEASE HELP IM DESPERATE- what is the same and different about these two parabolas

krok68 [10]

One is bigger than the other and they are the same shape

7 0

3 years ago

Question 11 of 15

SVEN [57.7K]

Carbon tetrahydride is B. CH4

5 0

3 years ago

Read 2 more answers

A 70.0-kg person throws a 0.0480-kg snowball forward with a ground speed of 33.5 m/s. A second person, with a mass of 55.0 kg, c

saw5 [17]

Answer:

The final velocity of the thrower is $\bf{3.88~m/s}$ and the final velocity of the catcher is $\bf{0.029~m/s}$ .

Explanation:

Given:

The mass of the thrower, $m_{t} = 70~Kg$ .

The mass of the catcher, $m_{c} = 55~Kg$ .

The mass of the ball, $m_{b} = 0.0480~Kg$ .

Initial velocity of the thrower, $v_{it} = 3.90~m/s$

Final velocity of the ball, $v_{fb} = 33.5~m/s$

Initial velocity of the catcher, $v_{ic} = 0~m/s$

Consider that the final velocity of the thrower is $v_{ft}$ . From the conservation of momentum,

$&& m_{t}v_{ft} + m_{b}v_{fb} = (m_{t} + m_{b})v_{it}\\&or,& v_{ft} = \dfrac{(m_{t} + m_{b})v_{it} - m_{b}v_{fb}}{m_{t}}\\&or,& v_{ft} = \dfrac{(70 + 0.0480)(3.90) - (0.0480)(33.5)}{70}\\&or,& v_{ft} = 3.88~m/s$

Consider that the final velocity of the catcher is $v_{fc}$ . From the conservation of momentum,

$&& (m_{c} + m_{b})v_{fc} = m_{b}v_{it}\\&or,& v_{fc} = \dfrac{m_{b}v_{it}}{(m_{c} + m_{b})}\\&or,& v_{fc} = \dfrac{(0.048)(33.5)}{(55.0 + 0.0480)}\\&or,& v_{fc} = 0.029~m/s$

Thus, the final velocity of thrower is $3.88~m/s$ and that for the catcher is $0.029~m/s$ .

8 0

3 years ago