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4 years ago

In which chemical equation is the number of atoms in the reactants the same as the number of atoms in the products?

Physics

2 answers:

klemol [59]4 years ago

7 0

I’m not very sure but I think it’s 4

Alik [6]4 years ago

3 0

The answer is the second one

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Electrons are important to electric current because they are able to

Agata [3.3K]

Electrons are important to the electric current because they are able to move from one atom to another. When an atom loses an electron, it becomes positively charged and when an atom gains an electron, it becomes negatively charged.

4 0

4 years ago

An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . Suppose that

RUDIKE [14]

Answer:

0.0241875 m

Explanation:

$m_1$ = Mass of quarterback = 80 kg

$m_2$ = Mass of football = 0.43 kg

$v_1$ = Velocity of quarterback

$v_2$ = Velocity of football = 15 m/s

Time taken = 0.3 seconds

In this system as the linear momentum is conserved

$m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.43\times 15}{80}\\\Rightarrow v_1=0.080625\ m/s$

Assuming this velocity is constant

$Distance=Velocity\times Time\\\Rightarrow Distance=0.080625\times 0.3\\\Rightarrow Distance=0.0241875\ m$

The distance the quarterback will move in the horizontal direction is 0.0241875 m

4 0

3 years ago

You leave the doctor's office after your annual checkup and recall that you weighed 689 N in her office. You then get into an el

son4ous [18]

Answer: 0.455 m/s^2

Explanation:

f = ma = m x 9.8=689 (the mass is constant)

m = 78.3

now on the elevator

f = 721 = m x a

a= 10.26

the elevator is moving down because there is a increase in weight. the acceleration of elevator = 10.26-9.8 = 0.455

8 0

4 years ago

If it takes 20 seconds to push the table across the room.What is the power ?

olchik [2.2K]

Answer: Its applied force and friction, The friction is the drag and the applied force is you pushing

3 0

3 years ago

The potential energy of a body of mass m is given by U(x) = -mgx + 1/2kx^2. The corresponding force is

jonny [76]

Answer:

F = (mg - kx) i ^

Explanation:

Force and potential are related

F = - ( $\frac{dU}{dx}$ i ^ + \frac{dU}{dy} j ^ + \frac{dU}{dz} k ^)

in this exercise we are told that the potential is

U = - m g x + ½ kx²

let's make the drive

\frac{dU}{dx} = -mg + kx

\frac{dU}{dy}= 0

\frac{dU}{dz} = 0

we substitute

F = (mg - kx) i ^

4 0

3 years ago