All categories

4 years ago

Sort the items based on whether they are simple machines or compound machines.

Physics

2 answers:

jonny [76]4 years ago

4 0

Simple machines : wheelbarrow seesaw and pair of tongs

Tom [10]4 years ago

3 0

Answer:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

Explanation:

Simple machine is the simplest device to use mechanical advantages. It has simplest mechanism to multiply the magnitude of force.

So, pair of tongs, seesaw and wheelbarrow are the example of simple machine because their mechanism is simplest.

Compound machine is a device that is made up of more than one simple machine.

so, sewing machine, fishing rod and reel and crane are example of compound machine because these devices shows more than one machine in it.

Thus, classification is as follows:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

You might be interested in

A heat engine is 20% efficient. If it loses 800 J to the cooling system and exhaust during each cycle, the work done by the engi

Maurinko [17]

Answer: A. 200J

Therefore, the workdone by the heat engine is 200J

Explanation:

Given ;

The efficiency of the heat engine is E = 20% = 0.2

Heat loss L= 800J

For an heat engine the efficiency is measured by the amount of workdone by the heat engine when compared to the heat generated.

Efficiency E = workdone/heat generated × 100%

Heat generated G= workdone W + heat loss L

G = W + L

According to the question.

W = 20% of G

W = 0.2G ......1

L = 80% of G

L = 0.8G

G = L/0.8 ......2

Substituting equation 2 to 1

W = 0.2(L/0.8)

And L = 800J

W = 0.2(800/0.8)

W = 200J

Therefore, the workdone by the heat engine is 200J

4 0

3 years ago

The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0

monitta

Use Coulomb law: F = k * q1*q2 / (r^2), where k = 9.00 * 10^9 N.m^2/C^2

F = 9.00 * 10^9 N.m^2/C^2 * 2.4*10^-8 C * 1.8*10^-6 C / [0.008m]^2 = 38.88 * 10^ -5 N

F = 39 * 10 -5N

4 0

3 years ago

Read 2 more answers

A 15lb bowling ball and a 10 pound bowling ball are

emmasim [6.3K]

Same time
..................

5 0

3 years ago

A mass m at the end of a spring vibrates with a frequency

Wittaler [7]

Answer:

m = 0.59 kg.

Explanation:

First, we need to find the relation between the frequency and mass on a spring.

The Hooke's law states that

$F = -kx$

And Newton's Second Law also states that

$F = ma = m\frac{d^2x}{dt^2}$

Combining two equations yields

$a = -\frac{k}{m}x$

The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.

$\omega = \sqrt{\frac{k}{m}}$

And given that ω = 2πf

the relation between frequency and mass becomes

$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$ .

Let's apply this to the variables in the question.

$0.88 = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\\0.60 = \frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}\\\frac{0.88}{0.60} = \frac{\frac{1}{2\pi}\sqrt{\frac{k}{m}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}}\\1.4667 = \frac{\sqrt{m+0.68}}{\sqrt{m}}\\2.15m = m + 0.68\\1.15m = 0.68\\m = 0.59~kg$

6 0

3 years ago

According to Newton’s first law of motion, what will an object in motion do when no external force acts on it?

Sedaia [141]

Answer:

object will remain in the motion if no external force acts on it for ex(roughness of surface,air resistance) according to inertia ,inertia is a that property of matter that continues its existing state either in rest or motio

3 0

3 years ago