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kipiarov [429]
2 years ago
7

What type of device is a coal-fired power plant?

Physics
2 answers:
MrMuchimi2 years ago
6 0
The answer for your question is D. the heat engine that uses heat to do work
Alex777 [14]2 years ago
4 0
I think the answer is D
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A student is performing experiments on a particular substance. Which
boyakko [2]

Answer: A.

Explanation:

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Help pls i’m not sure what to do
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2 years ago
Indiana jones (83.5 kg) is running 3.75 m/s when he jumps in a stationary 312 kg mine cart. what is their joint velocity afterwa
Lubov Fominskaja [6]

Answer:

.7917 m/s

Explanation:

This is a conservation of momentum question. You have an object initially at rest (cart) so that object is initially at 0 momentum. Indiana Jones is 83.5 kg and running 3.75 m/s so he starts with a momentum of 313.125 kg * m/s because momentum is equal to mass * velocity. Once the person jumps in the cart, the cart and the person can be considered one object and by conservation of momentum, the momentum of the Indiana-cart system is equal to 313.125 kg * m/s. By that, we can set that momentum equal to the combined mass * joint velocity. So 313.125 = (83.5kg + 312kg) * joint velocity. Then just solve for the velocity. The answer should be smaller than the intial velocity of the person of 3.75 m/s because the mine cart is HUGE at 312kg.

3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Joules could be used to measure
lyudmila [28]

All of the above, work is a measurement of energy transfer, in Joules.

Potential energy = Joules

Kinetic energy = Joules

The key thing here is that anything having to do with just energy or energy transfer is measured in joules.

4 0
2 years ago
Three charges, each of magnitude 10 nC, are at separate corners of a square of edge length 3 cm. The two charges at opposite cor
FinnZ [79.3K]

Answer:

The force exerted by three charges on the fourth is F_{resultant}=2.74\times10^{-5}\ \rm N

Explanation:

Given:

  • The magnitude of three identical charges, q=10\ \rm nC
  • Length of the edge of the square a=3 cm
  • Magnitude of fourth charge ,Q=3 nC

According to coulombs Law the force F between any two charge particles is given by

F=\dfrac{kQq}{r^2}

where r is the radial distance between them.

Since the force acting on the charge particle will be in different directions so according to triangle law of vector addition

F_{resultant}=\sqrt ((\dfrac{kQq}{L^2})^2+(\dfrac{kQq}{L^2} })^2)+\dfrac{kQq}{(\sqrt{2}L)^2}\\F_{resultant}=\dfrac{kQq}{L^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=\dfrac{9\times10^9\times10\times10^{-10}\times3\times10^{-9}}{0.03^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=2.74\times 10^{-5}\ \rm N

5 0
2 years ago
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