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IRINA_888 [86]
3 years ago
11

PLEASE HELP!!!!!

Mathematics
1 answer:
goblinko [34]3 years ago
7 0

Answer: The electroscope had a negative charge before the experiment started.  When the negatively charged rod comes near the electroscope more electrons are repelled down to the metal pieces and the metal pieces move farther away from each other.

 Step-by-step explanation: First of all, how we know the answer is not A or B is because unlike charges attract each other which means the metal pieces would not spread out. Now that we narrowed it down to C and D we can find the answer, In answer choice D it states that the negatively charged rod attracted the electrons from the electroscope, if that happened then something would happen to the rod, not the electroscope. In answer choice C it says that the rod repels the electrons downward on to the metal pieces, which would cause the metal pieces to spread out since they are both negative. Sorry, I'm not the best with explaining, I hope you understand.

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The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

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