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Step2247 [10]
3 years ago
15

Please help as soon as possible! Kia's plant is 8 1/5 inches tall and is growing 2/3 of an inch each week. Lyric's plant is 10 7

/10 inches tall and is growing 1/6 inch each week. Write and solve an equation to find how many weeks it will take for the height of the two plants to be the same.
Equation:___________

Solution:___________

I know I'm using y=mx+b but how would I write out my answer and I'm just confused on how I'd solve this.
Mathematics
1 answer:
boyakko [2]3 years ago
6 0
To find the answer, you find out the height of the plants for each week until they're the same.

Equation: Growth × Week + Original Height

For Kia: 2/3w + 8 1/5
For Lyric: 1/6w + 10 7/10
Kia:
Week 0 = 8 1/5 in.
Week 1 = 8 13/15 in.
Week 2 = 9 8/15 in.
Week 3 = 10 1/5 in.
Week 4 = 10 13/15 in.
Week 5 = 11 8/15 in.

Lyric:
Week 0 = 10 7/10 in.
Week 1 = 10 13/15 in.
Week 2 = 11 1/30 in.
Week 3 = 11 1/5 in.
Week 4 = 11 11/30 in.
Week 5 = 11 8/15 in.

Solution: 5 Weeks
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Answer:

The graph is attached Below and the plotting is given below.

Step-by-step explanation:

Given:

-9x + 6y = 18

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To draw a line on a graph the required minimum two points but here we will have three points as point A, point B, and point C.

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Put x = -4 in the given equation we get

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For point B

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∴ y=\frac{0}{3}\\ \\y=0

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For point C

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3 years ago
The first ingredient you will need to make a cake is flour. Imagine the recipe says you will need 4 cups of it. When you look at
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Step-by-step explanation:

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Veronica has two offers for a $65,000 student loan. The first loan has a 6.3% interest rate for 15 years, and the second loan ha
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The second option has a lower amount of interest paid.

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N = number of years  

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2 years ago
"If a ball is thrown into the air with a velocity of 44 ft/s, its height in feet t seconds later is given by y = 44t − 16t2. (a)
Nataly_w [17]

Answer:

i) -28 ft/s

ii) -21.6 ft/s

iii) -20.8 ft/s

iv) -20.16 ft/s

b)  -20 ft/s

Step-by-step explanation:

if v represents vertical velocity then if the height y is

y = 44*t − 16*t²

and the instant velocity v is the derivative with respect to the time

v= dy/dt = 44*(1) - 16*(2*t) = 44- 32*t

while the average velocity is va= (y-y₀)/(t-t₀)

where t₀ = 2 and y₀=y(t₀) =  44*2 − 16*2² = 24

then

va= (y-y₀)/(t-t₀) = (44*t − 16*t² -  24)/(t-2)

for

i) t= 0.5s + 2 s= 2.5 s

va = (44* 2.5  − 16* 2.5 ² -  24)/( 2.5 -2) = -28 ft/s

ii) t= 0.1s + 2 s= 2.1 s

va = (44* 2.1  − 16* 2.1 ² -  24)/( 2.1 -2) = -21.6 ft/s

iii) t= 0.05 s + 2 s= 2.05 s

va = (44* 2.05  − 16* 2.05 ² -  24)/( 2.05 -2) = -20.8 ft/s

iv) t= 0.01s + 2 s= 2.01 s

va = (44* 2.01  − 16* 2.01 ² -  24)/( 2.01 -2) = -20.16 ft/s

b) the instantaneous velocity when t=2

v (t=2) =  44- 32*(2) = -20 ft/s

6 0
2 years ago
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