Use photomath it’s an app on the app store
I did it on the calculator and the answer is 7.77777777778
48 because that's what you get following your equation in PEMDAS order :)
Answer:
5.44 cm³
Step-by-step explanation:
The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.
The area of a hexagon with side length s is given by ...
A = (3/2)√3·s²
For s=1 cm, the area is ...
A = (3/2)√3(1 cm)² = (3/2)√3 cm²
__
The area of a circle is given by ...
A = πr²
The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...
A = π(0.5 cm)² = 0.25π cm²
__
The volume is the face area multiplied by the length, so is ...
V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³
V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³
The volume of the metal is about 5.44 cm³.
Answer:
L = 25.959 inches
Step-by-step explanation:
Volume of first cube = 375 inch³
Volume of second cube = 648 inch³
Volume of third cube = 1029 inch³
We need to find the length of the stack of the cube shaped block.
We know that,
The volume of a cube = a³ (a is side of a cube)
![a_1=\sqrt[3]{375} \\\\=7.211\ \text{inches}](https://tex.z-dn.net/?f=a_1%3D%5Csqrt%5B3%5D%7B375%7D%20%5C%5C%5C%5C%3D7.211%5C%20%5Ctext%7Binches%7D)
![a_2=\sqrt[3]{648 } \\\\=8.653\ \text{inches}](https://tex.z-dn.net/?f=a_2%3D%5Csqrt%5B3%5D%7B648%20%7D%20%5C%5C%5C%5C%3D8.653%5C%20%5Ctext%7Binches%7D)
![a_3=\sqrt[3]{1029} \\\\=10.095\ \text{inches}](https://tex.z-dn.net/?f=a_3%3D%5Csqrt%5B3%5D%7B1029%7D%20%20%5C%5C%5C%5C%3D10.095%5C%20%5Ctext%7Binches%7D)
Hence, the total length of the stack is :
L = 7.211 + 8.653 + 10.095
= 25.959 inches
Hence, this is the required solution.
