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4 years ago

How does the angular diameter of an object change as you move away from the object?

Physics

2 answers:

GarryVolchara [31]4 years ago

6 0

Answer:

its B

Explanation:

7nadin3 [17]4 years ago

5 0

Explanation :

Angular diameter of a sphere or a circle shows how large a sphere or a circle appears from a given point. It is the angle between the initial and final positions.

The angular diameter of a given sphere or a circle is given by :

$\delta =2arc\ tan\dfrac{d}{2D}$

where $\delta$ is angular displacement

d is actual diameter of object

D is distance to the center of sphere

So, angular displacement is inversely proportional to the distance from the object.

Hence, as we move away from the object the angular diameter of an object gets smaller.

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Jane and John Doppler effect

UkoKoshka [18]

Answer:

To summarize, Jane's star has a red light and is traveling towards the Earth while John's star has a blue light and is traveling away from the Earth. This is a prime example of the Doppler Effect in motion. The stars look different because they are traveling in different directions.

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3 years ago

AuniformsphericalshellofmassM=4.5kgandradiusR=8.5cmcan rotate about a fixed vertical axis on frictionless bearings. A massless,

Kazeer [188]

Answer:

$v=1.42\frac{m}{s}$

Explanation:

There is no friction in the physical system. Thus, according to the law of conservation of energy, recall that the object is released from rest:

$\Delta E=0\\U=K_R+K_T\\mgh=\frac{I_p\omega_p^2}{2}+\frac{I_s\omega_s^2}{2}+\frac{mv^2}{2}$

Recall that the moment of inertia of a sphere is $I_s=\frac{2MR^2}{3}$ . The angular speed of the pulley is $\omega_p=\frac{v}{r}$ and the angular speed of the sphere is $\omega_s=\frac{v}{R}$ . So, we replace:

$mgh=\frac{I_pv^2}{2r^2}+\frac{2MR^2}{3}\frac{v^2}{2R^2}+\frac{mv^2}{2}\\mgh=v^2(\frac{I_p}{2r^2}+\frac{M}{3}+\frac{m}{2})\\v^2=\frac{mgh}{\frac{I_p}{2r^2}+\frac{M}{3}+\frac{m}{2}}\\\\v=\sqrt{\frac{(0.6kg)(9.8\frac{m}{s^2})(0.82m)}{\frac{3*10^{-3}kg\cdot m^2}{2(0.05m)^2}+\frac{4.5kg}{3}+\frac{0.6kg}{2}}}\\v=1.42\frac{m}{s}$

5 0

4 years ago

A student performs an experiment in which a 4kg object travels across a horizontal surface with an initial speed velocity of 6m/

Snezhnost [94]

Answer:

The velocity of the center of mass of the two-object system remains constant during the experiment.

5 0

3 years ago

a low tide and a high tide occur in the oceans two times each day. which factor has the greatest effect on the size of the tides

Dmitrij [34]

Answer:

The gravitational pull from the Moon has the greatest effect on the size of the tides.

Hope this helps, :)

7 0

3 years ago

5) [Honors]A seagull, ascending straight upward at 5.2 m/s, drops a shell when it is 12.5m above the ground. (A)

jolli1 [7]

Answer:

(B) 13.9 m

Explanation:

Given:

v₀ = 5.2 m/s

y₀ = 12.5 m

(A) The acceleration in free fall is -9.8 m/s².

(B) At maximum height, v = 0 m/s.

v² = v₀² + 2aΔy

(0 m/s)² = (5.2 m/s)² + 2 (-9.8 m/s²) (y − 12.5 m)

y = 13.9 m

v = at + v₀

-5.2 m/s = (-9.8 m/s²) t + 5.2 m/s

t = 1.06 s

3 0

3 years ago