Answer:
Correct answer is Wave A has a greater pitch and frequency
Explanation:
To understand the given figure, we should know the definition of wavelength, frequency and pitch
Wavelength
wavelength is defined as distance between two successive wave crests or troughs.
Frequency
Frequency is defined as the number of waves which passes through a given point per second. SI unit of frequency is Hertz.
Pitch
our ear understand the frequency of a sound wave as pitch. A a lower frequency sound has a lower pitch and a higher frequency sound has a higher pitch.
In given figure Wave A has lower wavelength and higher frequency so it have higher pitch than wave B.
Answer:
Fc=5253
N
Explanation:
Answer:
Fc=5253
N
Explanation:
sequel to the question given, this question would have taken precedence:
"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."
so we derive centripetal acceleration first
ac (centripetal acceleration) = v^2/r
make r the subject of the equation
r= v^2/ac
ac is 6.23*g which is 9.81
v is 101m/s
substituing the parameters into the equation, to get the radius
(101^2)/(6.23*9.81) = 167m
Now for part
( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.
he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.
Fc (Centripetal Force) = m*v^2/r
So (86kg* 101^2)/(167) =
Fc=5253
N
Answer:
Step down transformers are used in power adaptors and rectifiers to efficiently decrease the voltage. They are also used in electronic SMPS.
Explanation:
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Answer:
0.7 mJ
Explanation:
<u>Identify the unknown: </u>
The work required to turn the dial from 180° to 0°
<u>List the Knowns: </u>
Capacitance when the dial is set at 180°: C = 350 pF = 350 x 10^-12 F Capacitance when the dial is set at 0°: C = 100 pF = 100 x 10^-12 F
Voltage of the battery: V = 130 V
<u>Set Up the Problem:</u>
<em><u>Energy stored in a capacitor: </u></em>
U_c=1/2*V^2*C
=1/2*Q^2/C
<em><u>When the dial is set at 180°:</u></em><em> </em>
U_c=1/2*(130)^2*350*10^-12=10^-4
Q=√2*U_c*C=4*10^-7
<u><em>When the dial is set at 0°:</em></u>
U_c=1/2*(4*10^-7)^2/100*10^-12
=8*10^-4 J
<u><em>Solve the Problem: </em></u>
ΔU_c=7*10^-4 J
=0.7 mJ
note:
there maybe error in calculation but method is correct
unless...the wall simulaneiously exerts the same amount of force on you.