An astronaut lands on a new planet. The new planet’s mass is half that of the

1 answer:

7 0

Ah hah ! Very nice problem.

-- Since the mass is 1/2 of the Earth's mass, the gravitational forces between him
and the new planet would be 1/2 of what they are on Earth.

-- Since the distance between him and the center of the new planet is 1/2 of the
distance between him and the Earth's center, the gravitational forces between him
and the new planet would be (2)² = 4 times what they are on Earth.

-- These conditions combine to make his weight (1/2) x (4) = 2 times his earth weight.

-- He weighs 1,000 N (about 224.8 pounds) on the new planet.

(Maybe that's why they selected an astronaut for this mission who only weighs
about 112.5 pounds on Earth.)

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A crate with mass 32.5 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 14.0 N.

Sati [7]

Answer

given,

mass of crate = 32.5 Kg

horizontal force = 14 N

initial speed, u = 0 m/s

a) acceleration produced = ?

we know,

F = m a

$a = \dfrac{F}{m}$

$a = \dfrac{14}{32.5}$

a = 0.431 m/s²

b) using equation of motion

t = 10 s

$s = ut + \dfrac{1}{2}at^2$

$s = 0 + \dfrac{1}{2}\times 0.431\times 10^2$

s = 21.54 m

c) again using equation of motion

v = u + at

v = 0 + 0.431 x 10

v = 4.31 m/s

4 0

3 years ago

Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west en

Brut [27]

Answer:

The corridor's distance is "90 m".

Explanation:

She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1.
Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled.
Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop.
The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.
Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.

Now,

⇒ $2x + 2y = 60$