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sergey [27]
3 years ago
8

An astronaut lands on a new planet. The new planet’s mass is half that of the

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0
Ah hah !  Very nice problem.

-- Since the mass is 1/2 of the Earth's mass, the gravitational forces between him
and the new planet would be 1/2 of what they are on Earth.

-- Since the distance between him and the center of the new planet is 1/2 of the
distance between him and the Earth's center, the gravitational forces between him
and the new planet would be (2)² = 4 times what they are on Earth.

-- These conditions combine to make his weight  (1/2) x (4) = 2 times his earth weight.

-- He weighs 1,000 N (about 224.8 pounds) on the new planet.

(Maybe that's why they selected an astronaut for this mission who only weighs
about 112.5 pounds on Earth.)
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A baseball is moving at a speed of 2.2m/s when it strikes the catchers glove. The paddding of the glove is compressed by 24mm be
Andre45 [30]

Average acceleration of the baseball: -101 m/s^2

Explanation:

Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the displacement of the object

For the baseball in this problem, we have:

u = 2.2 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

s = 24 mm = 0.024 m is the displacement of the ball while decelerating

Therefore, we can solve for a to find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{0-2.2^2}{2(0.024)}=-101 m/s^2

where the negative sign means the baseball is slowing down.

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4 0
3 years ago
1000 millicoulombs of charge passes through a point. The amount of current passing through the point is
Rzqust [24]

The amount of current passing through the point is 1 A

The amount of current passing through the point can be calculated using the formula below.

⇒ Formula:

  • Q = i/t......................... Equation 1

⇒ Where:

  • Q = Charge
  • i = current
  • t = time.

⇒ Make "i" the subject of the equation.

  • i = Qt....................... Equation 2

From the question,

⇒ Given:

  • Q = 1000 millicoulombs = 1 coulombs
  • t = 1 seconds. (Assuming the time is 1 seconds)

⇒ Substitute these values into equation 2

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Hence, The amount of current passing through the point is 1 A.

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2 years ago
WILL GIVE YOU BRAINLIST IF YOU ANSWER Which of the following characteristics of the Arctic rabbit is specifically an adaptation
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Answer:

Hold active layer of soil in place; act as producers in ecosystem

5 0
3 years ago
On the earth, when an astronaut throws a 0.250 kg stone vertically upward, it returns to his hand a time T later. On planet X he
Igoryamba

Answer:\frac{g}{2}

Explanation:

Given

mass of stone\left ( m\right )=0.250 kg

Let initial velocity with which it is thrown upward is u

therefore after time t it's velocity is zero at highest point

t=\frac{u}{g}

where g= gravity at earth

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Now same thing is done in Planet X where gravity is g'

therefore time taken by stone to reach surface is

T'=T=2\times \frac{u}{g'}-------2

Divide 1 & 2

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g'=\frac{g}{2}

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