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sergey [27]
4 years ago
8

An astronaut lands on a new planet. The new planet’s mass is half that of the

Physics
1 answer:
tensa zangetsu [6.8K]4 years ago
7 0
Ah hah !  Very nice problem.

-- Since the mass is 1/2 of the Earth's mass, the gravitational forces between him
and the new planet would be 1/2 of what they are on Earth.

-- Since the distance between him and the center of the new planet is 1/2 of the
distance between him and the Earth's center, the gravitational forces between him
and the new planet would be (2)² = 4 times what they are on Earth.

-- These conditions combine to make his weight  (1/2) x (4) = 2 times his earth weight.

-- He weighs 1,000 N (about 224.8 pounds) on the new planet.

(Maybe that's why they selected an astronaut for this mission who only weighs
about 112.5 pounds on Earth.)
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1.) Calculate the work done in lifting a 200 N couch a distance of 1.3 m from a loading ramp.
Free_Kalibri [48]

Explanation:

work = force ×distance

1 w = ? f= 200 d= 1.3

w = f ×d

=200×1.3

= 269 joule

2 w=? f=40. d=6

w= 40/6

= 240 joule

3. w=? m=254. f= ? d=3

w=f=mg. f= 254×10. f= 2540

w=f×d

=2540×3

= 7620 joule

8 0
3 years ago
Read 2 more answers
(10%) Problem 10: A 7.25-kg bowling ball moving at 9.85 m/s collides with a 0.875-kg bowling pin, which is scattered at an angle
siniylev [52]

Answer

given,

mass of bowling ball = 7.25 Kg

moving speed of the bowling ball = 9.85 m/s

mass of bowling in = 0.875 Kg

scattered at an angle = θ = 21.5°

speed after the collision = 10.5 m/s

angle of the bowling ball

tan \theta_1 = \dfrac{-[m_2v_2Sin \theta_2]}{m_1v_1 - (m_2v_2cos \theta_2)}

tan \theta_1 = \dfrac{-[0.875\times 10.5 \times Sin 21.5^0]}{7.25\times 9.85 - (0.875\times 10.5 \times cos 21.5^0)}

tan \theta_1 = \dfrac{-[3.3672]}{62.86}

tan \theta_1 = 0.0536

\theta_1 =-3.066^0

b) magnitude of final velocity

v = \dfrac{-m_2v_2sin\theta_2}{m_1 sin\theta_1}

v = \dfrac{-0.875 \times 10.5 sin21.5^0}{7.25 sin(-3.066^0)}

v = 8.68 m/s

5 0
3 years ago
A 14.0 kg cart is coasting down a street at a steady speed of 7.00 m/s. what is the kinetic energy of the cart?
Orlov [11]
I had this question before can you show me the answer choices
3 0
4 years ago
What is the net force on an object<br> at rest?
Natasha2012 [34]

Answer:

Net force equals 0

Explanation:

Newton's first law states that an object at rest tends to remain at rest, and an object in motion tends to remain in motion with a constant velocity (constant speed and direction of motion), unless it is acted on by a nonzero net force. Note that the net force is the sum of all the forces acting on an object.

4 0
4 years ago
Read 2 more answers
A manufacturer provides a warranty against failure of a carbon steel product within the first 30 days after sale. Out of 1000 so
hodyreva [135]

Answer:A) Risk(R)= $1000

B) There is justification for spending an additional cost of $100 to prevent a corrosion whose consequence in monetary terms is $1000

Explanation:R= Risk,

P=Probability of failure

C= Consequence of failure

Mathematically, R=P ×C

10 out of 1000 carbon-steal products failed

Probability of failure= 10/1000 =0.01

The consequence of failure by corrosion given in monetary term =$100,000

Risk of failure = 0.01 × $100,000

R=$1000

4 0
3 years ago
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