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3 years ago

7

calculate the mass of air in a room if the floor dimensions are 10m × 12m and height is 400 cm the density of air is 1 .26 kg/M³

3

1 answer:

Burka [1]3 years ago

6 0

Explanation:

first find the volume of room --->

$v \: = 10 \times 12 \times (400 \times {10}^{ - 2} ) \times = 480 \: {m}^{3}$

then find the mass

$mass \: = \: density \: \times \: volume \: = 480 \times 1.26 = 604.8 \: kg$

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The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The

True [87]

Answer:

Explanation:

Capacitance of capacitor

= ε₀ A / d , ε₀ is permittivity of space , A is area of plate , d is distance between plates.

= 8.85 x 10⁻¹² x 2 x 10⁻³ / (6 x 10⁻³)

= 2.95 x 10⁻¹² F

Electric field E = V / d , V is potential difference

V = E x d

= 100 x 10³ x 6 x 10⁻³

= 600 V

Charge on the capacitor

= capacitance x potential difference

= 2.95 x 10⁻¹² x 600

= 17.7 x 10¹⁰ C

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3 years ago

A racetrack has the shape of an inverted cone, as the drawing shows. On this surface the cars race in circles that are parallel

sergey [27]

Answer:

The value of d is 183.51 m.

Explanation:

Given that,

Speed of car = 34.0 m/s

Suppose The car race in the circle parallel to the ground surface is at an angle 40°

The radius of circular path $r = d\cos\theta$

Normal force acting on the car = N

We need to calculate the value of d

Using component of normal force

The horizontal component of normal force is equal to the gravitational force.

$N\cos\theta=mg$ ....(I)

The vertical component of normal force is equal to the centripetal force

$N\sin\theta=\dfrac{mv^2}{r}$ .....(II)

Divided equation (I) by equation (II)

$\tan\theta=\dfrac{v^2}{gr}$

Put the value of g

$\tan\theta=\dfrac{v^2}{g\times d\cos\theta}$

$v^2=\tan\theta\times g\times d\cos\theta$

$v^2=g\times d\sin\theta$

$d=\dfrac{v^2}{g\sin\theta}$

Put the value into the formula

$d=\dfrac{(34.0)^2}{9.8\times\sin40}$

$d=183.51\ m$

Hence, The value of d is 183.51 m.

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3 years ago

Planet Tatoone is about 1.7 AU from its Sun. Approximately how long will it take for light to travel from the Sun to Tatoone in

Radda [10]

Answer:

The value is $t = 14.129 \ minutes$

Explanation:

From the question we are told that

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The speed of light is $c = 3.0*10^{8} \ m/ s$

Generally the time taken is mathematically represented as

$t = \frac{d}{c}$

=> $t = \frac{2.543*10^{11}}{3.0*10^{8} }$

=> $t = 847.7 \ s$

Now converting to minutes

$t = \frac{847.7}{60}$

=> $t = 14.129 \ minutes$

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3 years ago

How significant is air resistance for projectile motion?

miv72 [106K]

Answer:

Air resistance have some significant role in projectile motion if the motion lasts for some time.

Explanation:

Air resistance or air drag seems to be important in daily actvities and games like baseball.

The trajectory of the projectile with or without air resistance or air drag is totally different.

When we neglect air drag, the only acting force is gravity against the motion so the maximum height and range are suppose Hmax and R.

Now, when we consider air drag, it is important to notice that there are two forces against the motion of the ball and along the direction of gravity. It seems that both maximum height and range are lesser Hmax'< Hmax and R'<R.

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2 years ago

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Anika [276]

Answer:

B.

I think.

Explanation:

Mars doesn't have that much of an atmosphere!

Have a great day!

7 0

2 years ago