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oksano4ka [1.4K]
3 years ago
10

A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the

pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly
Physics
2 answers:
alexdok [17]3 years ago
5 0

Answer:

15 m/s

Explanation:

Given:

F = 0.7N   m = 0.25g = 0.0025kg   x = 40cm = 0.4m v_{0} = 0

Since F = ma, a = F/m = 0.7N/0.0025kg = 280m/s^{2}

Using the Big Five, v ^{2} = v_0^{2} + 2ax, v = \sqrt{0 + 2*280m/s^2*0.4m} = \sqrt{216} m/s=  15m/s

frosja888 [35]3 years ago
3 0

Answer:

Your answer would be

A person 40 cm- blows into the left end of the pipe to eject the marshmallow from the right end. ... A strain of sound waves is propagated along an organ pipe and gets reflected from an. play · like-icon ... The velocity of sound in air is 340ms^(-1). ... The two pipes are submerged in sea water, arranged as shown in figure. Pipe.Explanation:

I belive this is the answer sorry if im wrong!

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