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egoroff_w [7]
1 year ago
10

Might it be possible to explain the interaction of the rod and pieces of paper as a gravitational interaction? please explain wh

y you think that your answer is true.
Physics
1 answer:
mina [271]1 year ago
5 0

It is not possible  to explain the interaction of the rod and pieces of paper as a gravitational interaction.

<h3>What is Gravitational interaction?</h3>

This is defined as the interaction between a particle or body resulting from their mass. This type of interaction is usually weak and occurs in all distances possible.

It is not gravitational interaction, because the rod attracts paper only against the gravitational force of the earth and there is no attraction between both bodies under a different condition.

This is therefore the reason why it is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.

Read more about Gravitational interaction here brainly.com/question/25624188

#SPJ1

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ivanzaharov [21]

Answer:

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3 0
3 years ago
An ice skater is spinning at 6.00 rev/s with his moment of inertia being 0.400 kg/m2. Calculate his new moment of inertia if he
labwork [276]

Answer:

New moment of inertia will be I=1.92kgm^2

Explanation:

It is given initially angular velocity \omega =6rev/sec=6\times 2\pi =37.68rad/sec

Moment of inertia I=0.4kgm^2

Angular momentum is equal to L=I\omega =37.68\times 0.4=15.072kgm^2/sec

Now angular velocity is decreases to \omega =1.25rev/sec=1.25\times 2\times 3.14=7.85rad/sec

As we know that angular momentum is conserved

So 15.072=I\times 7.85

I=1.92kgm^2

So new moment of inertia will be I=1.92kgm^2

4 0
3 years ago
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Ann [662]

Answer:

D

Explanation:

One of the factors of increasing the rate of a reaction is increasing concentration. Therefore adding more people increases the number of people on the dance floor , therefore increasing the concentration increases the rate of reaction.

6 0
3 years ago
A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.
Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

F=mg

\dfrac{mv^2}{r}=mg

\dfrac{v^2}{r}=g

v=\sqrt{rg}

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

v=\sqrt{250\times9.8}

v=49.49\ m/s

Hence, The speed of space station floor is 49.49 m/s.

6 0
2 years ago
PlzHELP
Naddika [18.5K]
 Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.Displacement<span> is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

</span>To calculate displacement<span>, simply draw a vector from your starting point to your final position and solve for the length of this line. If your starting and ending position are the same, like your circular 5K route, then your </span>displacement<span> is 0. In physics, </span>displacement<span> is represented by Δs.
 
 For me to solve this I would need to know the time, but I can give you a handy displacement calculator I used that helped me. 
 
https://www.easycalculation.com/physics/classical-physics/constant-acc-displacement.php

Hope I helped. 

</span> 

8 0
2 years ago
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