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Fynjy0 [20]
3 years ago
12

Jeremy left his bike outside overnight. When he woke up in the morning, there were water drops on the seat. When he went to ride

his bike after lunch, he saw the water drops had disappeared. Which statement best describes what happened to the water? (2 points) a The energy from the sun caused the water drops to condense. b The energy from the sun caused the water on the seat to boil. c The energy from the sun cooled the water, causing it to evaporate. d The energy from the sun heated the water, causing it to evaporate.
Chemistry
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

d The energy from the sun heated the water, causing it to evaporate.

Explanation:

The correct description of what happened is that the energy from the sun heated the water and causes it to evaporate completely.

Evaporation is a phase change process in which liquid is converted to gases. This occurs when a liquid gains considerable amount of energy. The molecules then breaks free from the bond holding compound place.

  • Option A is wrong because the energy from the sun does not cause condensation i.e. change from gas to liquid.
  • The water on the seat does not boil, it simply evaporates. So, option B is wrong.
  • When heat energy is added, it does not cause cooling of water. So option C is wrong.
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Answer:

The correct answer is

B.

\Delta H=2(1072)+498 -4(799)

Explanation:

Enthalpy of reaction :

It is the amount of energy released/absorbed when one mole of the substance is formed from the reactant at a constant pressure.

The enthalpy of a reaction can be calculated using :

\Delta H=\Delta H_{reactants}-\Delta H_{products}

2CO+O_{2}\rightarrow 2CO_{2}

\Delta H_{reactants}=2(C\equiv O)+O=O

\Delta H_{reactants}=2(1072)+498

H_{products}=2(2\times C=O)

H_{products}=4\times 799

\Delta H=\Delta H_{reactants}-\Delta H_{products}

\Delta H=2(1072)+498 -4(799)

units = \frac{kJ}{mole}

Please note that :

The carbon monoxide , CO should be taken as C triple bond O. Not C=O .

So , the bond energy =1072 is used

\Delta H=2(1072)+498 -4(799)

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