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kykrilka [37]
3 years ago
5

Porque as vezes nos da borboletas no estomago?

Chemistry
1 answer:
nexus9112 [7]3 years ago
8 0

Answer:

No haces literalmente, pero metepóricamente, su forma de hablar, lo que significa que tienes un sentimiento no argumental hacia algunos. La resonancia detrás de esto es que algunas personas pueden encontrar atractiva a una persona concreta o tener una buena personalidad, así que comienzas a asimilar esos sentimientos.

Explanation:

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Write structures for the following compounds.(a) 3-ethyl-4-methylhexane (b) 3-ethyl-5-isobutyl-3-methylnonane(c) 4-tert-butyl-2-
frutty [35]

Answer:

Find attached answer to this question.

Explanation:

a. 4-Isopropyloctane has a chain of eight carbons, with an isopropyl group on the fourth carbon.

5-tert-Butyldecane has a chain of ten carbons, with a tert-butyl group on the fifth.

CH3

4-isopropyloctane

CHCH3 CH3

CH3 CH3CH2CH2CH2CH2CH2 CH

5-tert-butyldecane

CH3 CH3CH2CH2CH2CH2CH2CH2CH2 CH

CCH3 CH3

3-3 Nomenclature of Alkanes 93

di- means 2 tetra- means 4 hexa- means 6

tri- means 3 penta- means 5 hepta- means 7

b. Using this rule, we can construct names for some complicated structures. Let\u2019s fin-

ish naming the heptane on p. 90, shown here in the margin. This compound has an ethyl

group on C3 and three methyl groups on C2, C4, and C5. List the ethyl group alphabeti-

cally before the methyl groups, and give each of the four substituents a location number.

Problem-solving Hint

When substituents are alphabetized,

iso- is used as part of the alkyl group

name, but the hyphenated prefixes

are not. Thus, isobutyl is alphabetized

with i, but n-butyl, tert-butyl, and sec-

butyl are alphabetized with b. The

number prefixes di-, tri-, tetra-, etc.

are ignored in alphabetizing.

CH3 CH

2-bromobutane

Br

CH2CH3 CH3 CH

3-chloro-2-methylpentane

CH3 Cl

CH CH2CH3 CH3 CH

1,2-difluoropropane

F

CH2F

c. CH2CH(CH3)2CH2CH3

CH CHCH2 CH2 CH2CH3 CH3

S O LV E D P R O B L E M 3-2

Give a systematic (IUPAC) name for the following compound.

SOLUTION

The longest carbon chain contains eight carbon atoms, so this compound is named as an octane.

Numbering from left to right gives the first branch on C2; numbering from right to left gives

the first branch on C3, so we number from left to right.

CH CH2

CH3

CH CH CH2CH3

CH CH3

CH3

CH3

CH3

3-ethyl-2,4,5-trimethylheptane

7

65

4 3

2

1

CH3

CH3

CH3 CH3

CH3

CH3

CH3

CH

CH CH CH

CH2CH3

CH2

C

d. CH3 CH3

CH3

CH2 CH2 CH2 CH2 CH2

CH2

CH

CH3 CH3CH

CH

CH3 CH

Br CH2CH3

CH CH3(b)

CH3CH2

CH2CHCH3 CH3

8 0
4 years ago
Read 2 more answers
Differences between hypothesis and theory​
Sphinxa [80]

Answer:

A hypothesis is either a suggested explanation for an observable phenomenon, or a reasoned prediction of a possible causal correlation among multiple phenomena. In science, a theory is a tested, well-substantiated, unifying explanation for a set of verified, proven factors.

Explanation:

He I hope this helps and hope I can brainliest answer

7 0
3 years ago
Read 2 more answers
(1) Complete the word equation for the complete combustion of methane in
Deffense [45]

Cooled in ice to help the water vapour condense. Tube 2 – contains lime water, goes cloudy to show the presence of carbon dioxide. Word equation: (hydrocarbon + oxygen → carbon dioxide + water) Methane + oxygen → carbon dioxide + water.

6 0
3 years ago
Can someone help me with this?
Anvisha [2.4K]
With what? I don’t see a photo or such.
8 0
3 years ago
1. 100gm of a 55% (M/M) nitric acid solution is to be diluted to 20% (M/M) nitric acid.
stealth61 [152]

Answer:

The volume of water to be added is 0.175 liters of water

Explanation:

The given concentration of the nitric acid = 55% (M/M)

The mass of the nitric acid solution = 100 gm

The concentration solution is to diluted to = 20% (M/M)

The 100 g 55%(M/M) nitric acid solution gives 55g nitric acid in 100 g of solution

Therefore, to have 20% (M/M) nitric acid solution with the 55 g nitric acid, we get

Let "x" represent the volume of the resulting solution, we have;

20% of x = 55 g of nitric acid

∴ 20/100 × x = 55 g

x = 55 g × 100/20 =  275 g

The mass of extra water to be added = The mass of the 20%(M/M) solution solution of nitric acid - The current mass of the 55%(M/M) solution of nitric acid

The mass of extra water to be added = 275 g - 100 g = 175 g

Volume = Mass/Density

The density of water ≈ 1 g/ml

∴ The volume of water to be added that gives 175 g of water =  175 g/(1 g/ml) = 175 ml. = 0.175 l

The volume of water to be added = 0.175 liters of water.

3 0
3 years ago
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