Answer:
I believe the answer is frequency
Hope this helps!! (let me know if it is right)
Explanation:
To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

Where,
B= Magnetic Field
l = length
= Vacuum permeability
= Vacuum permittivity
Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

Recall that the speed of light is equivalent to

Then replacing,


Our values are given as




Replacing we have,



Therefore the magnetic field around this circular area is 
The average rate of change of distance over the time interval
3 ≤ t ≤ 6 represents the coin's average velocity over that interval.
Explanation:
It is given that,
Weight of the rock in air, W = 110 N
Since, W = mg


m = 11.22 kg
We need to find the apparent weight of the rock when it is submerged in water. Apparent weight is equal to the weight of liquid displaced i.e.

d is the density of water, 
V is the volume of rock, 

M = 3.37 kg
The apparent weight in water, W = m - M

W = 76.93 N
So, the apparent weight of the rock is 76.93 N. Hence, this is the required solution.