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3 years ago

What happens when all the external forces on a system are balanced ?

1 answer:

5 0

Equilibrium refers to a state in which all of the external forces on an object all balance each other such that there is no net effect (net force equals 0). An object in equilibrium will not experience acceleration, and will either remain at rest, or continue moving at a constant velocity. Here's a simple example, pick up a book (or any random object) and hold it up in the air. The book is now in equilibrium, the downwards force of gravity is perfectly countered by the upwards force that you are applying to it. Notice that the object neither falls nor goes upwards (i.e. no acceleration). Now let go of the book, notice how it falls downwards till it hits the ground (or whatever was beneath it). That is because without the upwards force applied by your hand, the object is no longer in equilibrium, and the force of gravity takes over until it is in equilibrium again.

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Determina el trabajo realizado al desplazar un bloque 3 m sobre una superficie horizontal, si se desprecia la fricción y la fuer

bija089 [108]

Answer: El trabajo realizado al desplazar el bloque es: 75 N.m

Datos:

Fuerza= F= 25 N

Distancia= d= 3 m

Explicación:

El trabajo es el producto de la fuerza ejercida sobre un cuerpo con el desplazamiento producido por la fuerza. Para que exista trabajo, la dirección de la fuerza debe ser igual a la dirección del desplazamiento.

Trabajo= Fuerza x Desplazamiento

Reemplazando los datos:

T= 25 N * 3 m

T= 75 N.m

5 0

3 years ago

A particle travels along the x-axis in such a way that its acceleration at time t is a(t) = t + t2. if it starts at the origin w

Olegator [25]

The acceleration of the particle as a function of time t is
$a(t) = t + t^2$
The velocity of the particle at time t is the integral of the acceleration:
$v(t) = \int {a(t)} \, dt = \frac{t^2}{2} + \frac{t^3}{3} + C$
where the constant C can be found by requiring that the velocity at time t=0 is v=3:
$v(0) = 3$
and we find $C=v_0=3$
so the velocity is
$v(t)=3+ \frac{t^2}{2}+ \frac{t^3}{3}$

The position of the particle at time t is the integral of the velocity:
$x(t)=\int {v(t) } \,dt = 3t + \frac{t^3}{6}+ \frac{t^4}{12} +D$
where D can be found by requiring that the initial position at time t=0 is zero:
x(0)=0
from which we find D=0, so
$x(t)=3t + \frac{t^3}{6}+ \frac{t^4}{12}$

To solve the problem, now we just have to substitute t=5 into x(t) and v(t) to find the position and the velocity of the particle at t=5.

The position is:
$x(5)=3(5) + \frac{5^3}{6}+ \frac{5^4}{12}=87.92$
and the velocity is:
$v(5) = 3+ \frac{5^2}{2}+ \frac{5^3}{3}=57.17$

6 0

3 years ago

Which of the following is an example of a cultural control of pests?

Novay_Z [31]

the answer is keeping homes clean

8 0

3 years ago

Read 2 more answers

How are pendulums used in society? Give an example of a real-world pendulum that transfers a lot of energy.

mart [117]

Answer:

An old clock that has a swinging pendulum

Explanation:

7 0

3 years ago

Biologists use ball-and-stick models to study complex molecules by representing atoms with balls and bonds with sticks. DNA is a

AleksAgata [21]

One of the major limitations of using the ball and stick model for DNA, is that within a single double stranded segment of DNA, one would have to use many many balls to represent atoms that are present in the sugar phosphate backbone, along with all of the main atoms that compose the nitrogenous bases of DNA, we also cannot construct or show the helical form of DNA, by using balls and sticks as well.

7 0

3 years ago