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zloy xaker [14]
3 years ago
11

A car has a mass of 1200kg what is it’s acceleration when the engine exerts a force of 600 n

Physics
1 answer:
fredd [130]3 years ago
4 0

<u>Answer:</u>

0.5 ms−2

<u>Explanation</u>:

Newton's second law of motion is mathematically expressed as

F = ma ; where F is the force exerted on an object, m is the mass of the object, and a is the acceleration of that object.

In this case, the mass of the car and the force exerted on it are provided as information.

Let's plug in the values into the formula

F = ma :

⇒600

N =1200

kg × a

Let's express N

using SI base units:

⇒600 kg m s−2 = 1200 kg × a

⇒600 kg m s−2 = 1200 kg = 1200 kg

1200 kg × a

⇒1 on 2 ms −2 = 1 × a

∴ a = 0.5 ms−2

Therefore, the acceleration of the car is

0.5 ms−2

when its engine exerts a force of 600N

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A single photon interacts with a single electron and ejects it only if its energy is greater than work function. So, the increase in no. of photons per second means an increase in the intensity of laser beam. And greater no. of photons, will interact with greater no. of electrons. So, <u>the no. of ejected electrons per second will increase.</u>

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Answer:

vb = 22.13 m/s

So, the only thing that was measured here was the height of point A relative to point B. And the Law of Conservation of Energy was used.

Explanation:

In order to find the speed of roller coaster at Point B, we will use the law of conservation of Energy. In this situation, the law of conservation of energy states that:

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(1/2)vₙ² + ghₐ = (1/2)(vb)² + g(hb)

where,

vₙ = velocity of roller coaster at point a = 0 m/s

hₙ = height of roller coaster at point a = 25 m

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vb = velocity of roller coaster at point B = ?

hb = Height of Point B = 0 m (since, point is the reference point)

Therefore,

(1/2)(0 m/s)² + (9.8 m/s²)(25 m) = (1/2)(vb)² + (9.8 m/s²)(0 m)

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What does the potential energy and kinetic energy of an object depend on ?
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Answer:

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4 0
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