The heavier it is the more frictions it creates sliding on the floor. this make more kinetic energy.
The correct answer for this question would be option A. When Barry is
conducting an experiment and rolls a tennis ball down a ramp, the
statement that best describes the motion of the tennis ball is that, i<span>t does not exhibit projectile motion and follows a straight path down the ramp. Hope this helps.</span>
Answer: D = 16m
Explanation: given values: a = 2 m/s2, v = 4 m/s
In this case we have to determine the diameter of the Ferris wheel.
Diameter of circle is given as: D = 2.r.
First we have to find radius of wheel. The best way to find that is using the centripetal acceleration equation: a = v2/r
Plug in values in above equation to find radius: 2 m/s2 = (4 m/s)2/r 2 m/s2 = (16 m2/s2)/r r = (16 m2/s2)/2 m/s2
r = 8.0m
Diameter of Ferris wheel is:
D = 2.r.
D = 2.8m
D = 16m
Answer:
Radius, 
Explanation:
It is given that,
Magnetic field, B = 0.275 T
Kinetic energy of the electron, 
Kinetic energy is given by :


v = 1037749.04 m/s
The centripetal force is balanced by the magnetic force as :




So, the radius of the circular path is
. Hence, this is the required solution.