Answer:
1/36
Step-by-step explanation:
When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.
The coefficient of the squared term is 1/36.
Answer:
24
Step-by-step explanation:
tbh I am not sure if this is right but here
Answer:
<h2>7 square units</h2>
Step-by-step explanation:
As you can observe in the image attached, we know the coordinates of each vertex of the triangle.
To find the area using only its vertex coordinates, we need to use the following formula

Where the coordinates are

Replacing coordinates, we have
![A=\frac{1}{2}[1(0 -5)+4(5 -1 )+3(1-0 ) ]\\A=\frac{1}{2} [-5+16+3]=\frac{1}{2}(14)\\ A=7](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B1%280%20-5%29%2B4%285%20-1%20%29%2B3%281-0%20%20%29%20%20%5D%5C%5CA%3D%5Cfrac%7B1%7D%7B2%7D%20%5B-5%2B16%2B3%5D%3D%5Cfrac%7B1%7D%7B2%7D%2814%29%5C%5C%20A%3D7)
Therefore, the area of the triangle is 7 square units. So, the right answer is the second choice.