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3 years ago

Find the derivative of g(t)=3t^2+2t at t=-1 algebraically

Mathematics

1 answer:

levacccp [35]3 years ago

3 0

Answer:

Step-by-step explanation:

If y = ax^n then the derivative y' = anx^(n-1)

g(t) = 3t^2 + 2t so the derivative g'(t)

2*3 t^(2-1) + 2t(1-1)

= 6t + 2

At t =1 its value is 6 + 2 = 8.

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Nonamiya [84]

Answer:

GD = 6 in.

Step-by-step explanation:

Because the lines are medians AG = 2GD.

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Answer:

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Step-by-step explanation:

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