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3 years ago

The first mechanistic step in the direct reaction of an amine with a carboxylic acid to produce an amide is ________.

Chemistry

1 answer:

Effectus [21]3 years ago

5 0

Answer:

The first step is - option A) an acid base reaction.

Explanation:

The direct reaction of a carboxylic acid with an amine to form an amide is expected to be difficult as it would deprotonate the carboxylic acid and make a nonreactive carboxylate.

The first step in this reaction would be an acid - base reaction as protonation of the carbonyl carbon, that involves the interchange of proton in between electric charge or neutral compound, it is also known as protonation or deprotonation. The acid base reaction is followed by the nucleophilic attack on the carbonyl carbon.

Thus, The first step is - option A) an acid base reaction.

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A pressure gauge at the top of a vertical oil well registers 140 bars (=14 MPa). The oil well is 6000 m deep and filled with nat

Natalija [7]

Answer:

a) 336.6 MPa

b) 345.87 MPa

Explanation:

Given:

Pressure at the top of a vertical oil well = 140 bars =14 MPa

Depth of the oil well = 6000 m

Depth of the natural gas = 4700 m

Density of oil, ρ = 700 kg/m³

Temperature at the bottom of the well, T = 15° C = 15 + 273 = 288 K

Compressibility factor for natural gas, Z=0.80

molecular weight of natural gas = 18.9

Now,

Z= $\frac{\textup{PV}}{\textup{RT}}$

P is the pressure 14 MPa = 14000000 Pa

V is the volume

T is the temperature

R is the ideal gas constant = 8.314 J / (mol·K)

on substituting the respective values, we get

0.80 = $\frac{14000000\times\textup{V}}{8.314\times\textup{288}}$

V = 1.36 × 10⁻⁴ m³

Now,

Assuming for 1 kg of natural gas

Density of natural gas will be equal to reciprocal of the volume obtained i.e

Density of gas = $\frac{\textup{1}}{\textup{1.36}\times10^{-4}}$

Density of gas, ρₐ = 7308.62 Kg/m3

Therefore,

a) Pressure at natural gas-oil interface

P₁ = ρₐ × g × h

at the interface, h = 4700 m.

therefore,

Pressure at natural gas-oil interface, P₁ = 7308.62 × 9.81 × 4700

= 336949956 Pa

= 336.6 MPa

b) Pressure at the bottom of the well, P = P₁ + ( ρₐ × g × (6000 - 4700) )

P = 336949956 + ( 700 × 9.81 × (6000 - 4700) )

P = 345877056 Pa

P = 345.87 MPa

3 0

3 years ago

Explain the relationship between monomers and polymers using polysaccharides as an example

Mars2501 [29]

Answer:

Glucose and glycogen.

Explanation:

Hello,

Monomers are the functional molecules forming the polymers when an random amount of units (monomers) are linked form an assembly (polymer).

This could be exposed by considering the glucose as the monomer forming the glycogen which is a polymer that serves as a form of energy storage in animals, fungi, and bacteria; it is constituted by about 30,000 units of both lineal and branched glucose which provide many features that the glucose doesn't have by itself.

Best regards.

7 0

3 years ago

Which solution has the greater concentration?

WITCHER [35]

The higher concentrated solution is 0.250 mole LiCl dissolved in 250 ml of solution

( B).0.250mole of LiCl diluted in 250ml solution

<u>Explanation:</u>

<u>Procedure to find the intensity of the solution:</u>

To find the intensity of the solution, we have to use the following formula

M1V1=M2V2

250mL of a 0.500 M aqueous solution of LiCl is diluted with water

$M1V1=(250) \times (0.500)=125M$

250 ml of a 0.250M aqueous solution of LiCl is diluted with water

$M2V2=(250) \times (0.250)=62.5M$

Thus the PH level of a solution increases from ascending order, Therefore the Solution with 62.5M is a higher concentration than that of the solution with 125M.

7 0

4 years ago

The change in state from a solid to a liquid is called

Sidana [21]

Answer:

melting

Explanation:

3 0

3 years ago

What's the basic oxide

Anon25 [30]

Answer:

Basic oxides are oxides that show basic properties in opposition to acidic oxides and that either react with water to form a base; or react with an acid to form a salt and water which are called neutralization reactions.

Explanation:

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3 0

3 years ago

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