Answer:
The mass of heavier isotope is 345.6 amu.
Explanation:
Given data:
atomic wight of compound = 342.38 amu
lighter isotope mass = 340.91 amu
abundance of lighter isotope = 68.322%
mass of heavier isotope = ?
Solution:
average atomic mass = ( % age abundance of lighter isotope × its atomic mass) + (% age abundance of heavier isotope × its atomic mass) / 100
percentage of heavier isotope = 100- 68.322 = 31.678
Now we will put the values in formula.
342.38 = (68.322× 340.91) + (31.678 × X) / 100
342.38 = 23291.65302 + (31.678 × X) / 100
342.38 × 100 = 23291.65302 + (31.678 × X)
34238 -23291.65302 = (31.678 × X)
10946.35 / 31.678 = X
345.6 = X
The mass of heavier isotope is 345.6 amu.
Answer:
b. electronegativity
Explanation:
The ability of an atom in a molecule to attract electrons is best quantified by the _Electronegativity_.
Electronegativity is the ability of an atom to attract a shared pair of electron which is loosely held. Polar molecules often possess such properties. The Halogen group (group 17) is famous for such property because it has the highest electronegativity in periodic table.
1) Hydrocarbon: CH3 - CH2 - CH2 - CH2 - CH3
2) Only single bonds => alkane => sufix ane
3) no substitutions
4) 5 carbons = > prefix penta.
Therefore, the name is pentane.
