Answer : The value of
for this reaction is 36.18 kJ
Explanation :
First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.
As per first law of thermodynamic,
![\Delta E=q+w](https://tex.z-dn.net/?f=%5CDelta%20E%3Dq%2Bw)
where,
= internal energy of the system
q = heat added or rejected by the system
w = work done
As we are given that:
q = 38.65 kJ
w = -2.47 kJ (system work done on surrounding)
Now put all the given values in the above expression, we get:
![\Delta E=38.65kJ+(-2.47kJ)](https://tex.z-dn.net/?f=%5CDelta%20E%3D38.65kJ%2B%28-2.47kJ%29)
![\Delta E=36.18kJ](https://tex.z-dn.net/?f=%5CDelta%20E%3D36.18kJ)
Therefore, the value of
for this reaction is 36.18 kJ
The question deals with isotopes and how their masses differ from their normal elemental counterparts.
Here, T represents tritium, which is an isotope of hydrogen with a mass of 3 amu. Similarly, the isotope of oxygen present is ¹⁷O, which means it has a mass of 17 amu.
To determine the mass of this molecule, we do the following calculation:
3 * 2 + 17 * 2
6 + 34
40
The mass of T₂¹⁷O₂ is 40 amu
Ammonium magnesium phosphate hexa-hydrate usually looses its water of crystallization in a gradual manner. At the temperature above 100 degree Celsius the compound would have lost all its water of crystallization.<span />
Answer:
The answer is: A - Dimensions of the paper.
Explanation:
"A" is the independent variable because it is the only thing that you are manipulating in each trial (i.e. folding the paper in half each time). "B" is the dependent variable because it is what you are measuring in every trial. "C" and "D" remain constant (they aren't changed at all) so they are neither dependent or independent variables.