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Artyom0805 [142]
4 years ago
5

When a container is filled with 3 moles of helium gas, 2 moles of oxygen gas, and 1 mole of carbon dioxide gas, the pressure in

the container is 786 kPa. What is the partial pressure of the oxygen gas?
A. 131 kPa
B. 262 kPa
C. 393 kPa
D. 786 kPa
Chemistry
2 answers:
zhenek [66]4 years ago
8 0
<span>The mole fraction of oxygen gas is 2/6 =1/3, because there are 6 total moles of gas in the container. The partial pressure can be found by multiplying this mole fraction by the total pressure. So the answer is B. 262 kPA because 1/3(786)=262.</span>
Karolina [17]4 years ago
5 0

Answer:

B. 262 kPa

Explanation:

First we must find the total of moles in the container:

3 moles of helium + 2 moles of oxygen + 1 mole s of carbon = 6 moles.

of the total of moles, 2 are oxygen, so the fraction of oxygen in the container is 2/6 = 1/3

Thus, the partial pressure of the oxygen gas must be a third of the total pressure in the container:

Partial pressure of the oxygen gas = \frac{786kPa}{3} = 262 kPa\\

The answer is B. 262 kPa

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<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

<u>Explanation:</u>

We are given:

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The chemical equation for the dissociation of barium hydroxide follows:

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1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

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To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M

Putting values in above equation, we get:

pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88

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