Answer:
x = 1
, y = 3 thus: A is your Anser
Step-by-step explanation:
Solve the following system:
{2 x + y = 5 | (equation 1)
x + y = 4 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x + y = 5 | (equation 1)
0 x+y/2 = 3/2 | (equation 2)
Multiply equation 2 by 2:
{2 x + y = 5 | (equation 1)
0 x+y = 3 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 2 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 1 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:
Answer: {x = 1
, y = 3
Given
Endpoints of the diameter (5,2) and (-7,4)
Step One
Find the center
Center = (x2 + x1)/2 , (y2 + y1)/2
x2 = -7; x1 = 5; y2 = 4; y1 = 2
Center = (-7 + 5)/2 ; (4 + 2)/2;
Center = (-1 , 3)
Step Two
Find the radius squared using the distance formula. Use (5,2) as the second point. The other point is the center.
Distance squared = (5 - - 1)^2 + (2 - 3)^2
Distance squared = ( 6)^2 + (-1 )^2
Distance squared = 37
Step Three
State the circle's formula
(x - - 1 )^2 + (y - 3)^2 = 37
(x + 1)^2 + (y - 3)^2 = 37
Answer: the answer is b
Step-by-step explanation: