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jeyben [28]
3 years ago
15

To find the value of the expression x + 0.07 when x has the value of 0.0002

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

0.07

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>+</u><u> </u><u> </u><u> </u><u>0.0002</u>

<u> = 0.0702</u>

Step-by-step explanation:

hope it helped u buddy

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Factor: X^3 + 216 <br><br> also, what kind of favoring is this called?
kondaur [170]

Answer:

Step-by-step explanation:

a³+b³=(a+b)(a²-ab+b²)

x³+216=x³+6³=(x+6)(x²-6x+6²)=(x+6)(x²-6x+36)

5 0
3 years ago
On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John
insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

     $H_{max}=\frac{v^2}{2g}$

     $H_{max} = \frac{(48)^2}{2 \times 12}$

               = 96 ft

b). Time he can stay in the air before hitting the ground is

   $T=\frac{2v}{g}$

  $T=\frac{2 \times 48}{12}$

     = 8 seconds

c).  Considering upward motion as positive direction.

     v = u + at

We find the time taken to reach the maximum height by taking v = 0.

     v = u + at

     0 = 16 + (12) t

     $t=\frac{16}{12}$

        $=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t =  $=\frac{4}{3} \ s$  , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$  feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0
3 years ago
Somebody pls help me and pls show work!<br> (no links)
miss Akunina [59]

Answer:

I think the answer is letter A.

8 0
2 years ago
Read 2 more answers
Two dice are rolled. Use the complement rule to find that the probability that the sum of the dice is less than 10.
Katarina [22]

Answer:

\dfrac{5}{6}

Step-by-step explanation:

When two dice are rolled, the sample space is

\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}

In total, 36 outcomes

First, find the probability that the sum is 10 or greater:

All favorable outcomes

10: (4,6),\ (5,5),\ (6,4)

11: (5,6),\ (6,5)

12: (6,6)

In total, 6 outcomes.

The probability that the sum is 10 or greater is

P(A)=\dfrac{6}{36}=\dfrac{1}{6}

Use the complement rule to find that the probability that the sum of the dice is less than 10:

P(A^C)=1-P(A)=1-\dfrac{1}{6}=\dfrac{5}{6}

6 0
3 years ago
What type of function has exactly one output for each input? Balanced, even, one-to-one, onto
Mrac [35]

Answer:

A balanced function

8 0
3 years ago
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