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2 years ago

To find the value of the expression x + 0.07 when x has the value of 0.0002

Mathematics

1 answer:

Dvinal [7]2 years ago

4 0

Answer:

0.07

+ 0.0002

= 0.0702

Step-by-step explanation:

hope it helped u buddy

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Finley's pumpkin had a mass of 6.56.56, point, 5 kilograms (\text{kg})(kg)left parenthesis, start text, k, g, end text, right pa

insens350 [35]

Answer:

40%

Step-by-step explanation:

Finley's pumpkin had a mass of 6.5 kg before he carved it.

After carving it, the pumpkin had a mass of 3.9 kg.

Now, we are asked to determine the % decrease in the mass of the pumpkin.

Therefore, the % decrease in mass is given by

$\frac{\textrm {Initial Mass - Final Mass}}{\textrm {Initial Mass}} \times 100= \frac{6.5 - 3.9}{6.5} \times 100 = 40$ %. (Answer)

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2 years ago

Zane took three typing tests and recorded the results as shown.

MAVERICK [17]

Answer:

Step-by-step explanation:

For test A, the unit rate is 30 words per minute divided by 4 minutes, or 7.5 words per minute.

Unit rate = 78 words/15 minutes = 5.2 words per minute for test B.

The unit rate for test C is 99 words/22 minutes, or 4.5 words per minute.

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2 years ago

If you make monthly payments of $1,000 for 10 years, determine the total payment over the lifetime of the loan.

marshall27 [118]

Hi there
Payment per year
1,000×12months=12,000

total payment over the lifetime of the loan.
12,000×10years=120,000

Hope it helps

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2 years ago

* What's the y-intercept of the following? 4x + 2y = 20

Marysya12 [62]

Answer:

(1, -10) hope this helps

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2 years ago

Read 2 more answers

This is really confusing me: Simplify so that your answers contain only positive exponents.

xxTIMURxx [149]

Answer:

see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

$a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}$

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

$23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9$

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2 years ago