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dimulka [17.4K]
4 years ago
15

5/6 divided by 2 3/10

Mathematics
1 answer:
Kazeer [188]4 years ago
8 0

Answer:

243 yay!!!!!!!!!!!!!!!!!!!!!!!!!

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Rolls are being prepared to go to grocery stores. Divide 72 rolls into 2 groups so the ratio is 3 to 5. (please include your wor
natali 33 [55]
\sf 3:5 \to 3x:5x\\\\3x +5 = 8x\\ 8x = 72\\ x = 9\\\\9\times 3 =27\\9\times 5 =45\\ 27+45=72\\\\so~ the~ 2~ groups ~are~ 27~ and~ 45
8 0
3 years ago
Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math
alex41 [277]

Answer:\frac{8}{3}\times \sqrt{\frac{2}{5}}

Step-by-step explanation:

Given two upward facing parabolas  with equations

y=6x^2 & y=x^2+2

The two intersect at

6x^2=x^2+2

5x^2=2

x^2=\frac{2}{5}

x=\pm \sqrt{\frac{2}{5}}

area  enclosed by them is given by

A=\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx

A=\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx

A=4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]

A=\frac{8}{3}\times \sqrt{\frac{2}{5}}

7 0
3 years ago
Please help me with question 20. Thank you.
aleksley [76]

Answer:

B=208.72

Step-by-step explanation:

June 22

July: 22+ 22x (1+10%) = 46.2

Auq: 46.2+ 22 (1+10%) x (1+10%)= 72.82

Sep: 72. 82+ 22 (1+10%)³= 102.102

Oct: 102.102 + 22 x(1+10%)⁴= 134.3122

Nov: 134.3122 + 22×(1+10%)⁵= 169.74342

Dec:169.74342 +22(1×10%)⁶ =208.717762

=208.72

The calulation of Compound interest )

7 0
2 years ago
Find f(-5) if f( x ) = | x + 1|.
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

f(x)=x+1

then,

   f(-5)=(-5)+1

         =-4

8 0
2 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)
dybincka [34]

Answer:

amplitude; \frac{2}{3}

Phase shift; \pi units right

Period;\frac{2\pi}{3}

Step-by-step explanation:

The given function is

y=-\frac{2}{3}\cos(3t-3\pi)

This function is of the form;

y=A\sin (Bt+C)

The period is given by:

|A|=|-\frac{2}{3}|= \frac{2}{3}

The period is given by:

T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}

The phase shift is given by;

\frac{C}{B}=\frac{-\3pi}{3}=- \pi or \pi units right.

4 0
3 years ago
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