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Dmitry [639]
2 years ago
9

For the final part of the race, a handcyclist travels 32 feet each second across a distance of 400 feet. How many seconds does i

t take for the hand cyclist to travel the last 400 feet of the race
Mathematics
1 answer:
Elanso [62]2 years ago
5 0

Answer: 12.5 seconds


Step-by-step explanation:

Distance = rate * time. The distance is equal to 400 and the rate is 32 feet per second. So 400 = 32 * time. time = 400/32 = 12.5

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Which polynomial matches the expression -x(x – 5)?x2 – 5x x2 + 5x -x2 + 5x -2x – 5
Leno4ka [110]

Answer:

-x2 + 5x

Step-by-step explanation:

See below.

The graphs are the same

8 0
2 years ago
Amari claims that a rectangle is sometimes a parallelogram but a parallelogram is always a
Maslowich

Answer:

The statement is false.

Step-by-step explanation:

A parallelogram is a figure of four sides, such that opposite sides are parallel

A rectangle is a four-sided figure such that all internal angles are 90°

Here, the statement is:

"A rectangle is sometimes a parallelogram but a parallelogram is always a

rectangle."

Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.

The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.

The correct statement would be:

"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"

6 0
2 years ago
2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
There exist infinitely many common fractions $\frac{a}{b}$ , where $a > 0$ and $b > 0$ and for which $\frac{3}{5} < \fr
vredina [299]

Answer:

3/5 has the smallest denominator

Step-by-step explanation:

Question:

There exist infinitely many common fractions a/b , where a > 0 and b > 0 and for which 3/5 < a/b< 2/3. Of these common fractions, which has the smallest denominator? Express your answer as a common fraction.

Solution

A Common fraction is a rational number written in the form: a/b. Where a and b are both integers.

The denominator and numerator in this case are greater than zero. That is, they are non zeros.

The least common denominator (LCD) of two non- zero denominators is the smallest whole number that is divisible by each of the denominators.

To find the smallest denominator between 3/5 and 2/3, we would convert the fractions to equivalent fractions with a common denominator by finding their LCM (lowest common multiple).

When comparing two fractions with like denominators, the larger fraction is the one with the greater numerator and the smaller fraction is one with the smaller numerator.

In our solution after comparing, the smaller fraction would have the smallest denominator.

Find attached the solution.

3 0
3 years ago
Find the slope of the line through the pair of points. A(2, 3), P(2, 9)
AVprozaik [17]
A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\-------------------\\\\A(2;\ 3)\to x_1=2\ and\ y_1=3\\B(2;9)\to x_2=2\ and\ y_2=9\\\\m=\dfrac{9-3}{2-2}=\dfrac{7}{0}-divided\ by\ 0\\\\Answer:\ The\ slope\ unde fined. It's\ a\ vertical\ line\ x=2.
8 0
2 years ago
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