This question is checking to see whether you understand the meaning
of "displacement".
Displacement is a vector:
-- Its magnitude (size) is the distance between the start-point and
the end-point, no matter what route might have been followed along
the way.
-- Its direction is the direction from the start-point to the end-point.
Talking about the Earth's orbit around the sun, we can forget about
the direction of the displacement, and just talk about its magnitude
(size).
If we pretend that the sun is not moving and dragging the whole
solar system along with it, then what do we see the Earth doing
in one year ?
We mark the place where the Earth is at the stroke of midnight
on New Year's Eve. Then we watch it as it swings around through
this gigantic orbit, all the way around the sun, and in a year, it's back
to the same point that we marked !
So what's the magnitude of the displacement in exactly one year ?
It's the distance between the start-point and the end-point. But the
Earth came back to the same place it started from, so there's no
separation at all between the start-point and the end-point.
The Earth covered a huge distance in that year, but the displacement
is zero.
The concept required to solve this problem is that related to the Isobaric process. Isobaric process is understood as the process in which changes occur at constant pressure. From the first law of thermodynamics this can be expressed as,
Here,
P = Pressure
dV = Differential of Volume
As the Pressure is constant we have,
Replacing
Therefore the correct answer is A.
Rake bc it does not use anything no lever or anything
Answer:
d = 19.92 m
Explanation:
As in this exercise there is friction we must use the relationship between work and energy
W = ΔEm
Look for energy in two points
Initial. Fully compressed spring
Em₀ = = ½ k x²
Final. When the block stopped
= 0
Let's look for the work of the rubbing force
W = fr d cos θ
Since rubbing is always contrary to movement, θ = 180
W = - fr d
Let's use Newton's second Law, to find the force of friction
Y Axis
N- w = 0
N = mg
The equation for the force of friction is
fr = μ N
fr = μ mg
We substitute in the work equation
W = - μ m g d
We write the relationship of work and energy
-μ m g d = 0 - ½ k x²
d = ½ k x² / μ m g
Let's calculate
d = ½ 131 2.1 2 / (0.74 2 9.8)
d = 19.92 m
Answer:
What inferences can you make about the melting points of the different substances and the motion of their particles, based on the data? (ignore that needed it here so i could see it better.)
Explanation:
Butter has a lower melting point than the cheese and the wax. The motion of the cheese were a little separated while the butter articles have more space in between. The wax had the closest particles.
I dont know if that makes sense?