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kondor19780726 [428]
3 years ago
6

A 3.0kg mass is held 4.2 m above the ground. What is the potential energy of the mass with respect to the ground?

Physics
1 answer:
galina1969 [7]3 years ago
3 0
<h3><u>Answer;</u></h3>

126 joules

<h3><u>Explanation;</u></h3>

Potential energy is the energy possessed by a body while at rest.

It is calculated by the formula m×g×h; where m is the mass, h is the height and g is the gravitational acceleration, 10N/kg

Potential energy = m×g×h

                           = 3.0 × 4.2 × 10

                           <u>=  126 joules</u>

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Answer:

Explanation:

Electric field E = 4 x 10⁷ V / m

Dielectric constant k = 24

capacitance of capacitor

C = kε₀ A / d

d = plate separation

A =  plate area

C = .89 x 10⁻⁶

V / d = electric field

for minimum d , electric field will be maximum

V / d  = 4 x 10⁷

1930 / d = 4 x 10⁷

d = 1930 / 4 x 10⁷

d = 482.5 x 10⁻⁷ m

= 48.25 x 10⁻⁶ m

C = kε₀ A / d

.89 x 10⁻⁶ = 24 ε₀ A / d

A = .89 x 10⁻⁶  X d /  24 ε₀

A = .89 x 10⁻⁶  X 48.25 x 10⁻⁶  /  24  x 8.85 x 10⁻¹²

= 42.9 / 212.4

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3 years ago
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How do I find the velocity of a moving object?
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If you know the distance and the time I travelled that distance.


You just have to divide the time from the distance to get velocity

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How much does it cost to operate a 550 W Toaster for 6 hours. If electrical energy cost 12.0 cents per kW.H
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6.6 cents a month!!!

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What are some important factors to consider when choosing a warm-up before your workout?
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<u>Answer:</u>

Prior to exercise, a proper warm-up of 10-15 minutes is extremely important to avoid injuries.

  1. Don't go too hard in the beginning and boost your activity level slowly. A good indication of a proper warm-up is that you feel sweat on your body parts.
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6 0
4 years ago
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Tom has built a large slingshot, but it is not working quite right. He thinks he can model the slingshot like an ideal spring wi
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Answer:

8.9

Explanation:

We can start by calculating the initial elastic potential energy of the spring. This is given by:

U=\frac{1}{2}kx^2 (1)

where

k = 35.0 N/m is the initial spring constant

x = 0.375 m is the compression of the spring

Solving the equation,

U=\frac{1}{2}(35.0)(0.375)^2=2.5 J

Later, the professor told the student that he needs an elastic potential energy of

U' = 22.0 J

to achieve his goal. Assuming that the compression of the spring will remain the same, this means that we can calculate the new spring constant that is needed to achieve this energy, by solving eq.(1) for k:

k'=\frac{2U'}{x^2}=\frac{2(22.0)}{0.375^2}=313 N/m

Therefore, Tom needs to increase the spring constant by a factor:

\frac{k'}{k}=\frac{313}{35}=8.9

7 0
4 years ago
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