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3 years ago

10

Solve the equation for the variable.

" id="TexFormula1" title=" - 5.2x + 57.9 = 15.9 + 1.8x" alt=" - 5.2x + 57.9 = 15.9 + 1.8x" align="absmiddle" class="latex-formula">
x = [?]

2 answers:

svlad2 [7]3 years ago

3 0

Answer:

x = 6

Step-by-step explanation:

Given

- 5.2x + 57.9 = 15.9 + 1.8x ( subtract 1.8x from both sides )

- 7x + 57.9 = 15.9 ( subtract 57.9 from both sides )

- 7x = - 42 ( divide both sides by - 7 )

x = 6

arsen [322]3 years ago

3 0

Your best number is x= 6

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Write the equation of a line with a slope of 5/2 and passes through the point (2,3)

tamaranim1 [39]

Answer:

y - 3 = ⁵/₂(x - 2) {the point-slope form of the equation}

y = ⁵/₂x - 2 {the slope-intercept form of the equation}

5x - 2y = 4 {the standard form of the equation}

Step-by-step explanation:

The point-slope form of equation is: y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope.

m = ⁵/₂

(2, 3) ⇒ x₀ = 2, y₀ = 3

So, the point-slope form of the equation:

y - 3 = ⁵/₂(x - 2)

Therefore:

y - 3 = ⁵/₂x - 5 {add 3 to both sides}

y = ⁵/₂x - 2 ← the slope-intercept form of the equation

-⁵/₂x + y = - 2 {multiply both sides by (-2)}

5x - 2y = 4 ← the standard form of the equation

5 0

3 years ago

I NEED HELP ASAP MISSING ASSIGNMENTS HAVE TO BE TURNED IN TOMORROW \

Delvig [45]

Part 1: Circumference of circle = $105.20$ inches & Area of circle = $880.97 inches^{2}$

Part 2: Area of circle = $3.14 ft^{2}$

Part 3: Area of square not covered by circle = $29.69inches^{2}$ .

<u>Step-by-step explanation:</u>

<u>Part 1:</u>

We have radius of circle as $16\frac{3}{4} = 16.75 inches$ . Let's find area & circumference of circle:

Circumference of circle = $2\pi r$

⇒ Circumference of circle = $2\pi r$

⇒ Circumference of circle = $2\pi r$ = $2(3.14)(16.75)$

⇒ Circumference of circle = $105.20$ inches

Area of circle = $\pi r^{2}$

⇒ Area of circle= $\pi r^{2}$

⇒Area of circle = $\pi r^{2}$ = $(3.14)(16.75)^{2}$

⇒ Area of circle = $880.97 inches^{2}$

<u>Part 2:</u>

Circumference of circle = $2\pi r$ = $6.28ft$

⇒ $2\pi r = 6.28$

⇒ $r = \frac{6.28}{2\pi } = \frac{6.28}{2(3.14)} = 1 ft$

Area of circle = $\pi r^{2}$

⇒Area of circle = $\pi r^{2}$ = $(3.14)(1)^{2}$

⇒ Area of circle = $3.14 ft^{2}$

<u>Part 3:</u>

Perimeter of square = $4a$ , a is side of square.

⇒ $4a = 47$

⇒ $a = \frac{47}{4}$

⇒ a = $11.75 inch$

Since radius of circle inscribed in square is half of side of square i.e.

$radius = \frac{a}{2}\\ radius = r = \frac{11.75}{2}$

$r = 5.875inch$

Now, Area of square not covered by circle = Area of square - area of circle

⇒ $a^{2} - \pi r^{2}$

⇒ $11.75^{2} - 3.14(5.875)^{2}$

⇒ $29.69inches^{2}$

∴ Area of square not covered by circle = $29.69inches^{2}$ .

8 0

3 years ago

The set of points A (3, 0), B(-2, 10), C(0, 5) are collinear. True False

slavikrds [6]

This would be true. The points make up a straight line

3 0

3 years ago

Read 2 more answers

Michael just became a personal trainer and is finalizing his pricing plans. One plan is to charge $36 for the initial consultati

nexus9112 [7]

The cost will be same for one session. The cost will be $128.

Step-by-step explanation:

Given,

Initial consultation charges for Plan One = $36

Per session fee = $92

Let,

x be the number of sessions.

O(x) = 92x+36

Initial consultation charges for Plan Two = $86

Per session fee = $42

T(x) = 42x+86

For same cost;

O(x) = T(x)

$92x+36=42x+86\\92x-42x=86-36\\50x=50$

Dividing both sides by 50

$\frac{50x}{50}=\frac{50}{50}\\x=1$

Putting x=1 in T(x)

$T(1)=42(1)+86\\T(1)=42+86\\T(1)=128\\$

Putting x=1 in O(x)

$O(x) = 92(1)+36\\O(x) = 92+36\\O(x) = 128$

The cost will be same for one session. The cost will be $128.

Keywords: function, division

Learn more about functions at:

#LearnwithBrainly

5 0

3 years ago

Please help me with this in the math book it says “a triangle has two sides that are perpendicular. Could the triangle be isosce

Irina-Kira [14]

The triangle could be isosceles or scalene. It cannot be equilateral since all angles in that triangle would be 60 degrees. This prevents two sides from being perpendicular. Hope this helps!

3 0

3 years ago