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Sati [7]
3 years ago
10

Solve the equation for the variable.

" id="TexFormula1" title=" - 5.2x + 57.9 = 15.9 + 1.8x" alt=" - 5.2x + 57.9 = 15.9 + 1.8x" align="absmiddle" class="latex-formula">
x = [?]​
Mathematics
2 answers:
svlad2 [7]3 years ago
3 0

Answer:

x = 6

Step-by-step explanation:

Given

- 5.2x + 57.9 = 15.9 + 1.8x ( subtract 1.8x from both sides )

- 7x + 57.9 = 15.9 ( subtract 57.9 from both sides )

- 7x = - 42 ( divide both sides by - 7 )

x = 6

arsen [322]3 years ago
3 0
Your best number is x= 6
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For which value of a are the graphs of –4 = 3x + 6y and ax – 8y = 12 parallel?
Dimas [21]

Answer:

The answer is A) a=-4

Step-by-step explanation:


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3 years ago
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olga_2 [115]

Answer:

2. C

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3 years ago
2 cars leaving Hyland at the same time, one traveling North and the other going South. The 1st car is driving 6 mph faster than
oksian1 [2.3K]
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3 years ago
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Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 4 and 3−
Neko [114]

Answer:

P(x) = x^3 - 10x^2+ 34x-40

Step-by-step explanation:

Given

p =1 -- Leading coefficient

Zeros: 4\ and\ 3  - i

Required

Determine the polynomial

Represent the zeros with a and b

Such that

a = 4

b = 3 - i

The polynomial is:

P(x) = p * (x - a) * (x - b)

P(x) = 1 * (x - 4) * (x - (3 - i))

However, to solve further: We need to symmetrise over 3-i  and its conjugate

P(x) = 1 * (x - 4) * (x - (3 - i))* (x - (3 + i))

P(x) =  (x - 4) * (x - (3 - i))* (x - (3 + i))\\\\

To define a suitable function, the expression becomes

P(x) =  (x - 4) * ((x - 3)^2+1)

P(x) =  (x - 4) * ((x - 3)(x - 3)+1)

P(x) =  (x - 4) * (x^2 - 6x + 9+1)

P(x) =  (x - 4) * (x^2 - 6x +10)

Open bracket

P(x) = x^3 - 6x^2 +10x - 4x^2 + 24x-40

P(x) = x^3 - 6x^2  - 4x^2+10x + 24x-40

P(x) = x^3 - 10x^2+ 34x-40

5 0
3 years ago
From the given sides of 16, 14, and 21, determine what type of triangle it will form (right, acute, obtuse, none).
Komok [63]

Answer:

It is an acute triangle.

Step-by-step explanation:

It would be much easier for you to see where I'm getting at if you draw a diagram.

Assume this triangle is labelled ABC where a = 14, b = 21, and c = 16.

cos A = (16^2 + 21^2 - 14^2)/(2(16)(21))

∠A = cos^-1(0.82291...)

∠A ≅ 34.6°

cos B = 16^2 + 14^2 - 21^2)/(2(16)(14))

∠B = cos^-1(0.024...)

∠B ≅ 56.8°

∠C = 180 - (∠A + ∠B)

∠C ≅ 56.8°

Since there is no right-angle nor is there an obtuse angle,

Therefore the triangle is an acute triangle.

4 0
3 years ago
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