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2 years ago

PLEASE HeLP ME!!!! IM TIMED

Mathematics

1 answer:

ankoles [38]2 years ago

4 0

Answer:

4 units to the left

Step-by-step explanation:

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Y is equal to the additive inverse of 4x. Use this information to find the value of the expression 17x + 3y in terms of x.

nevsk [136]

Answer:

Step-by-step explanation:

The additive inverse of a function is that value added that will sum it up to zero

If y is the additive inverse of 4x, then y = -4x

Given the expression 17x+3y

Substitute y = -4x into the expression to have;

17x + 3(-4x)

17x -12x

Hence the value of the expression in terms of x is 5x

5 0

2 years ago

4/5 divided 8/7 HELP ASAP !!!

Leno4ka [110]

Answer:

7/10

Step-by-step explanation:

You can either use a calculator, or make both fractions have the denominator of 35 and change the two fractions to be,

$\frac{28}{35}$ and $\frac{40}{35}$ then divide.

Hope that helps and have a great day!

6 0

3 years ago

Read 2 more answers

Does anyone know how to solve this?

Oksi-84 [34.3K]

Answer: Okay so do 3x7.5 then 3x11.5 then 7.5x11.5 then add it up and you should get 143.25

3 0

1 year ago

A boat travels upstream for 48 miles in 3 hours and returns in 2 hours traveling downstream in a river. What is the rate of the

alekssr [168]

Answer:

20 mph and 4 mph

Step-by-step explanation:

GIVEN: A boat travels upstream for $48$ miles in $3$ hours and returns in $2$ hours traveling downstream in a river.

TO FIND: What is the rate of the boat in still water and the rate of the current.

SOLUTION:

Let the speed of boat in still water be $s$ and speed of current be $a$ .

$\therefore$ speed of water in upstream $=s+a$

speed of water in downstream $=s-a$

As $speed=\frac{distance}{time}$

$s+a=\frac{48}{3}=16$

$s-a=\frac{48}{2}=24$

Solving both we get

$s=20\text{ mph}$

$a=4\text{ mph}$

Hence speed of boat in still water and rate of current is 20mph and 4mph respectively.

3 0

3 years ago

If <br>4x+(y+x)=180<br>what is x? what is y?

uysha [10]

Step-by-step explanation:

$4x+(y+x)=180\\\\\text{Solve for}\ x:\\\\4x+y+x=180\qquad\text{combine like terms}\\\\(4x+x)+y=180\qquad\text{subtract}\ y\ \text{from both sides}\\\\5x=180-y\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{180-y}{5}\\\\\boxed{x=\dfrac{180-y}{5}}\\\\\text{Solve for}\ y:\\\\5x+y=180\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\\boxed{y=180-5x}$

7 0

2 years ago