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Anestetic [448]
3 years ago
15

Find the zeros of x^2+4x=-10 using the quadratic formula

Mathematics
2 answers:
ipn [44]3 years ago
7 0
X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6

Nookie1986 [14]3 years ago
6 0
X² + 4x = 10
x² + 4x - 10 = 10 - 10
x² + 4x - 10 = 0
x = <u>-4 +/- √(4² - 4(1)(-10))</u>
                   2(1)
x = <u>-4 +/- √(16 + 40)</u>
                 2
x = <u>-4 +/ √56
</u>             2<u>
</u>x =<u> -4 +/- √(4 × 14)</u>
               2
x = <u>-4 +/- √4 √14
</u>                2<u>
</u>x = <u>-4 +/- 2√14
</u>              2
x = <u>-4 +/- 2(3.741657387)</u>
                      2
x = <u>-4 +/- 7.483314774</u>
                    2
x = <u>-4 + 7.483314774 </u>   x = <u>-4 - 7.483314774</u>
                   2                                    2
x = <u>3.483314774</u>           x = <u>-11.483314774</u>
               2                                      2
x = 1.741657387           x = -5.741657387

<u />
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Natasha2012 [34]

Answer:

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=652.6 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size  

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

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A quadratic function f(x)=ax2 passes through (0,0) and (5,5). write an equation for this function
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Answer:

y = (1/5)x² or  y = x²/5

Step-by-step explanation:

We have the function f(x) = ax² and are given that the point (5,5) is on the parabola.  We need to find 'a'.   f(x) can be replaced with 'y', so we can rewrite the equation as...

y = ax²    

We know that when x = 5, y = 5, so we have

5 = a(5²)      now simplify...

5 = 25a

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1/5 = a, so our equation becomes

(1/5)x² or  x²/5  (the expressions are equal)

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