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Anestetic [448]
3 years ago
15

Find the zeros of x^2+4x=-10 using the quadratic formula

Mathematics
2 answers:
ipn [44]3 years ago
7 0
X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6

Nookie1986 [14]3 years ago
6 0
X² + 4x = 10
x² + 4x - 10 = 10 - 10
x² + 4x - 10 = 0
x = <u>-4 +/- √(4² - 4(1)(-10))</u>
                   2(1)
x = <u>-4 +/- √(16 + 40)</u>
                 2
x = <u>-4 +/ √56
</u>             2<u>
</u>x =<u> -4 +/- √(4 × 14)</u>
               2
x = <u>-4 +/- √4 √14
</u>                2<u>
</u>x = <u>-4 +/- 2√14
</u>              2
x = <u>-4 +/- 2(3.741657387)</u>
                      2
x = <u>-4 +/- 7.483314774</u>
                    2
x = <u>-4 + 7.483314774 </u>   x = <u>-4 - 7.483314774</u>
                   2                                    2
x = <u>3.483314774</u>           x = <u>-11.483314774</u>
               2                                      2
x = 1.741657387           x = -5.741657387

<u />
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Find the area of rectangle ABCD
satela [25.4K]

9514 1404 393

Answer:

  D. 12

Step-by-step explanation:

There are a number of ways to find the area of this rectangle. Perhaps the most straightforward is to find the lengths of the sides and multiply those. The distance formula is useful.

  d = √((x2 -x1)^2 +(y2 -y1)^2)

Using the two upper-left points, we find the length of that side to be ...

  d = √((3 -0)^2 +(3 -0)^2) = √(9 +9) = √18 = 3√2

Similarly, the length of the lower-left side is ...

  d = √((-2 -0)^2 +(-2 -0)^2) = √(4+4) = √8 = 2√2

Then the area of the rectangle is ...

  A = LW

  A = (3√2)(2√2) = 3·2·(√2)^2 = 3·2·2 = 12

The area of rectangle ABCD is 12.

_____

Other methods include subtracting the area of the corner triangles from the area of the bounding square:

  5^2 -2(1/2)(3·3) -2(1/2)(2·2) = 25 -9 -4 = 12

4 0
2 years ago
4/2 as a mixed number
balu736 [363]
Four halves equals 2.
6 0
3 years ago
Read 2 more answers
A florist has an order to make flower bouquets. the order calls for the use of 45 roses and 63 carnations. each bouquet made wil
Marta_Voda [28]
Find the GCF of both numbers
45-1,3,5,9,15,45
63-1,3,7,9,21,63
So each bouquet would have 9 of both rose and carnations
6 0
3 years ago
Help! Please! Geometry!!
DiKsa [7]

9.

By the Segment Addition Postulate, SAP, we have

XY + YZ = XZ

so

YZ = XZ - XY = 5 cm - 2 cm = 3 cm

10.

M is the midpoint of XZ=5 cm so

XM = 5 cm / 2 =  2.5 cm

11.

XY + YM = XM

YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm

12.

The midpoint is just the average of the coordinate A(-3,2), B(5,-4)

M = (A+B)/2 = \left( \dfrac{-3 + 5}{2}, \dfrac{2 + -4}{2} \right)

Answer: M is (1,-1)

You'll have to plot it yourself.

13.

For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.

AB^2 =(5 - -3)^2 + (-4 - 2)^2 = 8^2 + 6^2 = 100

Answer: AB=10

M is the midpoint of AB so

Answer: AM=MB=5

14.

B is the midpoint of AC.   We have A(-3,2), B(5,-4)

B = (A+C)/2

2B = A + C

C = 2B - A

C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)

Check the midpoint of AC:

(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good

Answer: C is (13, -10)

Again I'll leave the plotting to you.

5 0
3 years ago
How do I find A’?<br><br><br><br> Let U={a,b,c,d,e,f,g} and A={a,b,e,f}
vesna_86 [32]

Let U={a,b,c,d,e,f,g,h}

A={a,c,d}

B={b,c,d}

C={b,e,f,g,h}

6 0
3 years ago
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