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Arisa [49]
3 years ago
12

How do I factor 5x²-17x+6?

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0
5x^2-17x+6=0\ \ \ \ |write\ -17x\ as\ -15x-2x\\\\
5x^2-2x-15x+6=0\\\\\
x(5x-2)-3(5x-2)=0\\\\After\ factorization:\\ (x-3)(5x-2)=0
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3 years ago
in ABC the measure of angle A is 2x+3 the measure of angle B is 4x+2 the measure of angle C is 2x-1 what are the measures of the
Virty [35]


IN A triangle, sum of all angles = 180 degrees

2x + 3 + 4x+2 + 2x -1 = 180

8x +4  = 180

8x = 176

x = 176 /8 = 22 degrees

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7 0
3 years ago
Read 2 more answers
An electrician has a piece of wire that is 4 and 3/8 centimeters long. She divides the wire into pieces that are 1 and 2/3 centi
Vlada [557]

Answer:

She has approximately 3 pieces ( 2.625)

Step-by-step explanation:

To get the number of pieces, we need to divide the length of the wire by the individual length of the pieces.

To get the division done, it would be easier to convert what we have into improper fractions

For the piece of wire, the length which is 4 and 3/8 centimeters long will be 35/8 centimeters

while;

the individual length of each of the piece which is 1 and 2/3 centimeters long will be 5/3 centimeters

The number of pieces is thus 35/8 divided by 5/3 = 35/8 * 3/5 = 21/8 = 2.625 which is approximately 3 pieces

6 0
3 years ago
Evaluate the double integral. . ∫∫ y sqrt(x^2-y^2) dA, R={(x,y)|0≤y≤x, 0≤x≤1}. R. . Please explain
polet [3.4K]
First we will evaluate: ( substitution: u = x² - y²,  du = - 2 y dy )
\int\limits^x_0 {y \sqrt{ x^{2} - y^{2} } } \, dy= \\   \frac{-1}{2} \int\limits^x_0 { u^{1/2} } \, du  =
=\frac{-1}{3} \sqrt{ (x^{2} - y^{2} ) ^{3} } ( than plug in x and 0 )
=- \frac{1}{3} (  \sqrt{( x^{2} - x^{2}) ^{3}  }  -  \sqrt{ (x^{2} -0 ^{2} ) ^{3} } =
= 1/3 x³ ( then another integration )
1/3\int\limits^1_0 { x^{3} } \, dx = 1/3 (  x^{4}/4)}= 1/3 ( 1 ^{4}/4 - 0^{4} /4 )
= 1/3 * 1/4 = 1/12
4 0
3 years ago
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